I need help with the review questions and the formula is %change= change in volume (ml) / original volume (ml) x 100 Procedure1) Place water in a graduated cylinder and measure thevolume in mL (This will be your initial volume of water)2) Drop potato section into the graduated cylinder (Thiswill be your final volume of water)3) Calculate the volume of potato using the formula below.Volume of Potato = [Final volume of water (mL)] - [Initialvolume of water (mL)]***Remember to express your units!Example: 180mL150mL = 30mL-Review Questions that will be included in your lab reportare below.1) Describe what happens to a cell in a hypertonic solution.2) Describe what happens to a cell in a hypotonic solution.3) Describe what happens to a cell in an isotonic solution.4) If a cell has an osmotic pressure of 0.9% what willhappen to a cell when placed in each solution* 0.2 % solution* 0.4 % solution* 0.9 % solution* 9.0 % solution

Answered: 1) Describe what happens to a cell in a…

Biochemistry

9th Edition

ISBN:9781319114671

Author:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.

Publisher:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.

Chapter1: Biochemistry: An Evolving Science

Section: Chapter Questions

Problem 1P

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Question

I need help with the review questions and the formula is %change= change in volume (ml) / original volume (ml) x 100

Procedure
1) Place water in a graduated cylinder and measure the
volume in mL (This will be your initial volume of water)
2) Drop potato section into the graduated cylinder (This
will be your final volume of water)
3) Calculate the volume of potato using the formula below.
Volume of Potato = [Final volume of water (mL)] - [Initial
volume of water (mL)]
***Remember to express your units!
Example: 180mL
150mL = 30mL
-
Review Questions that will be included in your lab report
are below.
1) Describe what happens to a cell in a hypertonic solution.
2) Describe what happens to a cell in a hypotonic solution.
3) Describe what happens to a cell in an isotonic solution.
4) If a cell has an osmotic pressure of 0.9% what will
happen to a cell when placed in each solution
* 0.2 % solution
* 0.4 % solution
* 0.9 % solution
* 9.0 % solution

Expert Solution

Step 1

1) When the cell is put in hypertonic solution, the concentration of solutes in the solution is greater than the concentration of solutes in the cell, causing the cell to have reduced volume owing to the flow of water out of the cell.

2) When the cell is placed in hypotonic solution, the solute concentration outside the cell is smaller than the solute concentration inside the cell, causing the cell to acquire volume owing to water inflow.

3) When the cell is placed in isotonic solution, the solute concentration outside the cell equals the solute concentration inside the cell, resulting in no inflow or outflow of water and a steady volume in the cell.