1 dA , where R lies in the second quadrant and is bounded by the graphs of y = -x, the y-axis, and the circles R x2 x2 + y? + y? + 9 = 1 and x? + y? = 9. In polar coordinates, this integral has the form: 02 r2 . 1. f(r, 0) r drd® Enter the limits of integration (in the event one or more limits is not constant, use T for 0 ): rl = r2 = 01 = 02 = Enter f(r, 0) using T for 0 if needed: f(r, 0) = Enter the final value of the integral:

Q: Convert polar integral sin O cos Odrde to a cartesian integral. (a) | xydyde (b) [ xycxdy (c) [ |…

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Q: b) Evaluate the integral by converting in polar coordinates [T 13 dy dr

A: (1) tan−1⁡(x)=cot−1⁡(1/x)(2) tan−1⁡(x)+cot−1⁡(x)=π/2 (3) 1/sin⁡(x)=csc⁡(x) .

Q: calculate the area of polar equation r = 5-sin(theta)

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Q: Find the area inside both the polar rose r = 5 sin (20) and the curve r quadrant. Enter an exact…

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Q: Consider the polar curve r=2+ cos O (a) Sketch the curve (b) Set up and then evaluate an integral to…

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Q: Why is .5x.5.x.5x.5x.5 =0.03125 But .5x4=2 And 54=0.03125 Aren't they all the same equations just…

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Q: cos(0) – sin(0) between the lines 0 = 0 and 0 = 4 Find the area under the polar curve r = 5.

A: Explanation of the answer is as follows