(1) Consider the following series (1-a) The partial sums simplify to Sn Στα (104010) n=1 =1+(1/n) (1-b) If the series converges, enter the sum. If it diverges, enter INF, MINF or DNE. Remember to use INF to denote +∞ and MINF to denote -∞. n=1 - (In(10n+10) In(10n)) = 0 (2) Consider the following series 4 Σ n²+6n+8 n=1 (2-a) The partial sums simplify to Sn = (2-b) If the series converges, enter the sum. If it diverges, enter INF, MINF or DNE. 4 Ση 16η + 8 = 53/84 n=1

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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(1) Consider the following series
(1-a) The partial sums simplify to Sn
Στα (104010)
n=1
=1+(1/n)
(1-b) If the series converges, enter the sum. If it diverges, enter INF, MINF or DNE.
Remember to use INF to denote +∞ and MINF to denote -∞.
n=1
-
(In(10n+10) In(10n)) = 0
(2) Consider the following series
4
Σ
n²+6n+8
n=1
(2-a) The partial sums simplify to Sn
=
(2-b) If the series converges, enter the sum. If it diverges, enter INF, MINF or DNE.
4
Ση 16η + 8
= 53/84
n=1
Transcribed Image Text:(1) Consider the following series (1-a) The partial sums simplify to Sn Στα (104010) n=1 =1+(1/n) (1-b) If the series converges, enter the sum. If it diverges, enter INF, MINF or DNE. Remember to use INF to denote +∞ and MINF to denote -∞. n=1 - (In(10n+10) In(10n)) = 0 (2) Consider the following series 4 Σ n²+6n+8 n=1 (2-a) The partial sums simplify to Sn = (2-b) If the series converges, enter the sum. If it diverges, enter INF, MINF or DNE. 4 Ση 16η + 8 = 53/84 n=1
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