-1 Compound X has a molar mass of 416.41 g-mol and the following composition: element phosphorus chlorine 0 mass % 14.88% 85.12% Write the molecular formula of X. 00 X S

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**Chemical Composition Analysis of Compound X**

Compound X has a molar mass of \( 416.41 \, \text{g} \cdot \text{mol}^{-1} \) and consists of the following elements:

| Element    | Mass %  |
|------------|---------|
| Phosphorus | 14.88%  |
| Chlorine   | 85.12%  |

**Task:** Determine the molecular formula of compound X.

**Instructions for Calculation:**
To find the molecular formula, follow these steps:
1. Calculate the number of moles of each element based on the percentage composition and molar mass.
2. Determine the ratio of the moles of each element.
3. Write the empirical and then the molecular formula based on the calculated ratios.

For further explanation or assistance, please refer to the provided "Explanation" button or consult the guidelines on stoichiometric calculations in this section. Once you have determined the molecular formula, enter it in the provided input box and click "Check" to verify your answer.
Transcribed Image Text:**Chemical Composition Analysis of Compound X** Compound X has a molar mass of \( 416.41 \, \text{g} \cdot \text{mol}^{-1} \) and consists of the following elements: | Element | Mass % | |------------|---------| | Phosphorus | 14.88% | | Chlorine | 85.12% | **Task:** Determine the molecular formula of compound X. **Instructions for Calculation:** To find the molecular formula, follow these steps: 1. Calculate the number of moles of each element based on the percentage composition and molar mass. 2. Determine the ratio of the moles of each element. 3. Write the empirical and then the molecular formula based on the calculated ratios. For further explanation or assistance, please refer to the provided "Explanation" button or consult the guidelines on stoichiometric calculations in this section. Once you have determined the molecular formula, enter it in the provided input box and click "Check" to verify your answer.
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