1) (Choose only one answer) Why does a method to swap two array elements work correctly when a method to swap two integer values does not? a) Because arrays use more memory than primitive values. b) Because of a bug in Java. c) Because arrays are slower and more inefficient than primitives, so swapping is possible. d) Changes to an array parameter's elements will not be seen in the original array by the caller. e) Unlike integers, arrays are objects and use reference semantics.

Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
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How do you do this? JAVA
### Question 1

**Choose only one answer.**

**Why does a method to swap two array elements work correctly when a method to swap two integer values does not?**

a) Because arrays use more memory than primitive values.

b) Because of a bug in Java.

c) Because arrays are slower and more inefficient than primitives, so swapping is possible.

d) Changes to an array parameter's elements will not be seen in the original array by the caller.

e) Unlike integers, arrays are objects and use reference semantics.

**Answer:** e) Unlike integers, arrays are objects and use reference semantics.
Transcribed Image Text:### Question 1 **Choose only one answer.** **Why does a method to swap two array elements work correctly when a method to swap two integer values does not?** a) Because arrays use more memory than primitive values. b) Because of a bug in Java. c) Because arrays are slower and more inefficient than primitives, so swapping is possible. d) Changes to an array parameter's elements will not be seen in the original array by the caller. e) Unlike integers, arrays are objects and use reference semantics. **Answer:** e) Unlike integers, arrays are objects and use reference semantics.
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