1) Calculate the shear lag factor for the WT 180x36 tension member, with three lines of 20mm diameter bolts in drilled holes, as shown in Figure 2 (Exclude the bolt-holes). How does this factor compare with the shear lag factor given in SANS 10612-1-2011? Hence determine the design strength of the member, if the steel is Grade 350W. At what length will this member cease to satisfy the slenderness limitation? The dimensions and properties of the section are given below. o O G 65 60 60 40
1) Calculate the shear lag factor for the WT 180x36 tension member, with three lines of 20mm diameter bolts in drilled holes, as shown in Figure 2 (Exclude the bolt-holes). How does this factor compare with the shear lag factor given in SANS 10612-1-2011? Hence determine the design strength of the member, if the steel is Grade 350W. At what length will this member cease to satisfy the slenderness limitation? The dimensions and properties of the section are given below. o O G 65 60 60 40
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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Transcribed Image Text:1) Calculate the shear lag factor for the WT 180x36 tension member, with three lines of
20mm diameter bolts in drilled holes, as shown in Figure 2 (Exclude the bolt-holes). How
does this factor compare with the shear lag factor given in SANS 10612-1-2011? Hence
determine the design strength of the member, if the steel is Grade 350W. At what length
will this member cease to satisfy the slenderness limitation? The dimensions and properties
of the section are given below.
O
WT.180x36
tx
65
65
60 60 40
WT 180x36 dimensions and properties:
M = 36 kg/m; A = 4.55×10³ mm²; h= 175 mm; b= 204 mm; te= 15.1 mm; tw = 8.6 mm;
Ix = 10.3×106 mm¹; Zx = 73.1×10³ mm³; rx = 47.5 mm;
Iy = 10.7×106 mm¹; Zy = 105×10³ mm³; ry = 48.5 mm;
J = 300×10³ mm4; Cw= 286×106 mm; cx = 34.2 mm;
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