The following reactions all have K< 1.1) C9Н,04 (аq) + HCIO (aq) + НCН,04 (аq) + CIO (аq)2) NO (aq) + HС,Н,04 (аq) —HNO, (aq) + Coн-0, (аq)3) HСIO (аq) + NO; (aq) — СIO (aq) + HNO2 (aq)Arrange the substances based on their relative BASE strength.Clear AllHCIOHC,H¬O4strongest baseNO,intermediate baseCIO-weakest baseC,H¬O4not a Bronsted-Lowry baseHNO2

Answered: Image /qna-images/answer/7e183e7e-7ada-4bd1-a129-bad014aacd0a.jpg

Answered: 1) C9Н-О4 (аq) + HCIO (aq) — НС9Н-04…

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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0.5Ν2 (NH3 (g) H2 (g) + 1.5H2 (g) +1.2502 (g) (g) +0.502 (g) → NH3 (g) NO 2NO H2O (1) (g) (g) ΔΗ1° Use the data from the table above to determine AH° for the reaction below, expressed in terms of ΔΗ1°, ΔΗ2°, and ΔΗ3°. N2 (g) + O2 (g) + 1.5H2O (I)|ΔΗ2° ΔΗ3°
Given the enthalpies for the following reactions: 2 Fe (s) + 3/2 O₂(g) → Fe2O3 (s)Math output error AH₂ ΔΗ, CO (g) + 1/2 O₂ (g) → CO₂ (g) CO2 (g) ΔΗ = -248.7 kJ rxn rxn = 1,091.6 kJ Calculate the enthalpy change (AHrxn) for the following reaction: Fe2O3 (s) + 3 CO (g) → 2 Fe (s) + 3 CO₂ (g)
Find the enthalpy of reaction for the equation: H2SO4laq) + 2NAOH(aq)-Na,SO,(aq) + 2H20(), AH=? Using the following equations whose enthalpy is known (please round your answer to the tenths place): H2(g) + S(s) + 202(g) – H2SO,(aq), AH= -907.5 kJ Na(s)+ ½H2(g) + ½O2{g) – NaOH(aq), AH= -469.6 kJ 2Na(s) + S(s) + 20,(g) – Na,SOal(aq). AH= -1387.1 kJ H2(8) + ½O2(g) – H2O(1). AH= -285.8 kJ AH= kJ.
In a typical experiment performed to measure the electrical equivalent of heat, the following data are obtained: current drawn, 2.00 A; applied voltage, 3.00 V; mass of water, 122 g; mass of calorimeter, 30.8 g; specific heat of calorimeter, 0.100 cal/g Cº; time of run, 180 seconds; initial temperature of water, 25.5 °C; final temperature of mixture, 27.5°C. Find the value of J from these data.
4NH3(g) + 3O2(g) → 2N2(g) + 6H2O(l), ΔH = -1530kJmol-1 (1) H2(g) + 1/2O2(g) → H2O(l), ΔH = -288 kJmol-1 (2) Construct an enthalpy cycle and calculate the enthalpy of formation of ammonia.
Using the information below, calculate AH of NH3(g) + HCI(g) NH,CI(s). N, (8) + H, (8) NH,(g) AH = -46.19 kJ/mol > H, (g) + Cl,(8) → HCl(g) AH = -92.30 kJ/mol N, (8) + 2 H, (g) +Cl,(g) NH,Cl(s) AH = –314.4 kJ/mol • Your answer should have four significant figures. Provide your answer below: kJ/mol
Give typed solution not written
(1) C(s) + O2(g) CO2(8) AH, = -393.5 kJ AH = -283.0 kJ Using these data, calculate the enthalpy for the combustion of C to CO: (2) CO(g) + 02(8) CO2(8) - %3D (3) C(s) + 02(8) CO(g) AH3 = ? 24 - O A) 403.5 O B) 676.5 403.5 O D) 110.5 O E) -110.5
The enthalpy changes, AH, for three reactions are given. H, (g) + H, O(1) AH= -286 kJ/mol Ca(s) + 2 H*(aq) Ca2+(aq) + H, (g) Ca+(aq) + H, O(1) AH = -544 kJ/mol CaO(s) + 2 H*(aq) AH = -193 kJ/mol Using Hess's law, calculate the heat of formation for CaO(s) using the reaction shown. Ca(s) + O,(g) CaO(s) AH kJ/mol
Rank the elements or compounds in the table below in decreasing order of their boiling points. That is, choose 1 next to the substance with the highest boiling point, choose 2 next to the substance with the next highest boiling point, and so on. substance A B с D H :0: H | || | H с C -C-H 174 H H H chemical symbol, chemical formula or Lewis structure H H H | | C I 1 I H H H (II | Ag - Ar - :O: -O-H boiling point (Choose one) (Choose one) ✓ (Choose one) (Choose one) ✓
ہنا ہنا ہتا ہنر ۵۰۰ NaOH |
Consider the following reaction whose enthalpy change Is ΔΗ- w S(s) + H,(g) -> H,S(g) AH = w This equation is obtained using the following equations along with the Hess law H,(g) + %0,(g) -> H,0() AH = x S(s) + 0,(g) > So(g) AH = y ΔΗ Υ H,S(g) + 1%0,(g) -> H,O() + SO,(g) AH = z What is the relationship between enthalples w, x, y and z? O a. w=z+y -x O b. w=x + y -z O. W=S-Xx -y O d. w=x -y -z O e. w=z-y -x Clear my choice

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