**Physics Problem - Projectile Motion: Batman and the Batarang****Problem Statement:**4. Batman is leaping between two rooftops that are 6.70 m apart and have the same vertical height. He bounds from one to the next with a horizontal velocity of 9.4 m/s. He drops a batarang from his utility belt just as he leaves the first rooftop. His belt is 1.12 m above the two rooftops.**Questions:**a. How far below the rooftop does the batarang strike the second building? Assume its velocity is only in the horizontal direction.b. What is the batarang's total speed when it hits the second building?c. What angle below the horizontal does the batarang hit the building? (What is the angle of its final velocity?)d. Do the batarang and Batman reach the second building at different times? If so, which gets there first?**Explanation of Concepts Involved:***Projectile Motion Overview:*In this scenario, the batarang experiences projectile motion. The key aspects of projectile motion to consider are the horizontal and vertical components of the motion. The horizontal motion occurs at a constant velocity since there is no air resistance, while the vertical motion is influenced by gravity.To solve this, we need to employ the equations of motion separately for the horizontal and vertical components and then combine the results to find the total impact velocity and angle.*Diagrams and Graphs:*While no specific diagrams or graphs are provided within the image, it would be helpful to draw a basic sketch of the situation:1. Draw two buildings with a horizontal distance separating them.2. Indicate Batman jumping horizontally and dropping the batarang from a certain height above the roof level.3. Show the batarang’s parabolic trajectory.4. Mark the points of release and impact of the batarang.**Step-by-Step Solution:***Horizontal Motion:*- Horizontal distance (d) = 6.70 m- Horizontal velocity (v_x) = 9.4 m/sUsing the formula:\[ t = \frac{d}{v_x} \]Plug in the given values to find the time (t) taken to reach the second building.*Vertical Motion:*- Initial vertical position (h) = 1.12 m- Initial vertical velocity (v_y0) = 0 m/s (

Name: **Physics Problem - Projectile Motion: Batman and the Batarang****Pro
Uploaded: 2024-03-20T06:57:47.000Z
Channel: Bartleby
Description: **Physics Problem - Projectile Motion: Batman and the Batarang****Problem Statement:**4. Batman is leaping between two rooftops that are 6.70 m apart and have the same vertical height. He bounds from one to the next with a horizontal velocity of 9.4