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1 and cot 0 = Prove the reciprocal identities csc 0 = 1 sec 0 = sin 0 cos e tan 0 1 If P(x,y) is the point on the unit circle corresponding to 0, then use the definition of the sine and cosecant function to prove the reciprocal identity csc 0= sin 0 1 csc 0 = y 1 A. Since sin 0 = y and csc 0 = sin 0 1 B. Since sin 0 =x and csc 0 = 1 csc 0 = sin 0 1 and csc 0 =x, csc 0 = 1 C. Since sin 0 = sin 0 1 D. Since sin 0 = and csc 0 = y y csc 0 = sin 0 <1>

1 and cot 0 = Prove the reciprocal identities csc 0 = 1 sec 0 = sin 0 cos e tan 0 1 If P(x,y) is the point on the unit circle corresponding to 0, then use the definition of the sine and cosecant function to prove the reciprocal identity csc 0= sin 0 1 csc 0 = y 1 A. Since sin 0 = y and csc 0 = sin 0 1 B. Since sin 0 =x and csc 0 = 1 csc 0 = sin 0 1 and csc 0 =x, csc 0 = 1 C. Since sin 0 = sin 0 1 D. Since sin 0 = and csc 0 = y y csc 0 = sin 0 <1>

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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1 and cot 0 = Prove the reciprocal identities csc 0 = 1 sec 0 = sin 0 cos 0 tan 0 1 If P(x,y) is the point on the unit circle corresponding to 0, then use the definition of the sine and cosecant function to prove the reciprocal identity csc 0 = sin 0 1 csc 0 = y 1 A. Since sin 0 = y and csc 0 = sin 0 1 csc 0 = x' 1 B. Since sin 0 =x and csc 0= sin 0 1 C. Since sin 0 = 1 and csc 0=x, csc 0 = sin 0 1 D. Since sin 0 = and csc 0 = y y csc 0 = sin 0 <1>
Transcribed Image Text:1 and cot 0 = Prove the reciprocal identities csc 0 = 1 sec 0 = sin 0 cos 0 tan 0 1 If P(x,y) is the point on the unit circle corresponding to 0, then use the definition of the sine and cosecant function to prove the reciprocal identity csc 0 = sin 0 1 csc 0 = y 1 A. Since sin 0 = y and csc 0 = sin 0 1 csc 0 = x' 1 B. Since sin 0 =x and csc 0= sin 0 1 C. Since sin 0 = 1 and csc 0=x, csc 0 = sin 0 1 D. Since sin 0 = and csc 0 = y y csc 0 = sin 0 <1>
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