1 /* a[0] to a[aLength-1] is the array to sort */ int i,j; 2 3 int aLength; // initialise to a's length 4 5 /* advance the position through the entire array */ (could do i < aLength-1 because single element is also min element) */ for (i = 0; i < aLength-1; i++) { /* find the min element in the unsorted a[i .. aLength-1] */ 6 /* 7 8. 9 /* assume the min is the first element */ int jMin /* test against elements after i to find the smallest */ for (j = i+1; j < aLength; j++) 1 = i; 3 4 5 { /* if this element is less, then it is the new minimum */ if (a[j] < a[jMin]) 7 8. { /* found new minimum; remember its index */ 9. jMin = j; } 1 } 4 if (jMin != i) swap (a[i], a[jMin]); } 6 7 8 }
1 /* a[0] to a[aLength-1] is the array to sort */ int i,j; 2 3 int aLength; // initialise to a's length 4 5 /* advance the position through the entire array */ (could do i < aLength-1 because single element is also min element) */ for (i = 0; i < aLength-1; i++) { /* find the min element in the unsorted a[i .. aLength-1] */ 6 /* 7 8. 9 /* assume the min is the first element */ int jMin /* test against elements after i to find the smallest */ for (j = i+1; j < aLength; j++) 1 = i; 3 4 5 { /* if this element is less, then it is the new minimum */ if (a[j] < a[jMin]) 7 8. { /* found new minimum; remember its index */ 9. jMin = j; } 1 } 4 if (jMin != i) swap (a[i], a[jMin]); } 6 7 8 }
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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PLEASE CONVERT C CODE TO BASIC ASSEMBLY CODE. PLEASE PUT COMMENTS....
![/* a[0] to a[aLength-1] is the array to sort */
int i,j;
int aLength; // initialise to a's length
1
4
/* advance the position through the entire array */
6.
(could do i < aLength-1 because single element is also min element) */
for (i = 0; i < aLength-1; i++)
/*
7
8.
{
9.
/* find the min element in the unsorted a[i..
aLength-1] */
10
11
/* assume the min is the first element */
int jMin
/* test against elements after i to find the smallest */
for (j = i+1; j < aLength; j++)
12
= i:
13
14
15
{
/* if this element is less, then it is the new minimum */
if (a[j] < a[jMin])
16
17
18
{
/* found new minimum; remember its index */
jMin = j;
19
20
21
}
22
}
23
24
if (jMin != i)
25
{
swap (a[i], a[jMin]);
}
26
27
28
}](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fd4e0597c-c5a0-426d-bec7-238c0531da98%2Ff9f8ab1c-2190-4870-a75a-c7d90442fa74%2Fyc37na_processed.png&w=3840&q=75)
Transcribed Image Text:/* a[0] to a[aLength-1] is the array to sort */
int i,j;
int aLength; // initialise to a's length
1
4
/* advance the position through the entire array */
6.
(could do i < aLength-1 because single element is also min element) */
for (i = 0; i < aLength-1; i++)
/*
7
8.
{
9.
/* find the min element in the unsorted a[i..
aLength-1] */
10
11
/* assume the min is the first element */
int jMin
/* test against elements after i to find the smallest */
for (j = i+1; j < aLength; j++)
12
= i:
13
14
15
{
/* if this element is less, then it is the new minimum */
if (a[j] < a[jMin])
16
17
18
{
/* found new minimum; remember its index */
jMin = j;
19
20
21
}
22
}
23
24
if (jMin != i)
25
{
swap (a[i], a[jMin]);
}
26
27
28
}
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