1) A thick conducting spherical shell is inside of another thick conducting spherical shell as drawn below. Q1 = -0.300 C Q2 = +0.800 C RA = 0.10m Rc = 0.45m RB = 0.15m Rp = 0.50m A) Find the magnitude of the electric field at r=0.05m. B) Find the magnitude of the electric field at r=0.12m C) Find the magnitude of the electric field at r= 0.30m
1) A thick conducting spherical shell is inside of another thick conducting spherical shell as drawn below. Q1 = -0.300 C Q2 = +0.800 C RA = 0.10m Rc = 0.45m RB = 0.15m Rp = 0.50m A) Find the magnitude of the electric field at r=0.05m. B) Find the magnitude of the electric field at r=0.12m C) Find the magnitude of the electric field at r= 0.30m
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Transcribed Image Text:1) A thick conducting spherical shell is inside of another thick conducting
spherical shell as drawn below.
Q1 = -0.300 C
Q2 =+0.800 C
RA = 0.10m
RB = 0.15m
Rc =0.45m
Rp = 0.50m
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A) Find the magnitude of the electric field at r= 0.05m.
B) Find the magnitude of the electric field at r= 0.12m
C) Find the magnitude of the electric field at r= 0.30m
D) Find the magnitude of the electric field at r= 0.47m
E) Find the magnitude of the electric field at r= 0.62m
F) What is the flux through a Gaussian sphere of radius r= 1.000m?
G) What is the induced charge on the inner surface of the outer shell
(at r= 0.45m)?
Now imagine that the two conducting shells became insulators with the same
radii and charge values as before.
H) Circle below which of the answers above would have to be recalculated:
A
C
E
I) Explain why the answers you circled would be different with insulators.
Expert Solution
Step 1
Concept used:
Electric field inside the spherical shell is zero. It is non-zero on the surface and outside the spherical shell.
This follows from gaussian law.
NOTE: Out of given multiple parts, we solve only first three parts unless specified. You can resend the question for other parts to be solved.
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