1) A string is fixed at both ends and has a length of 2.34m. 2) The string vibrates at 80.6 Hz.
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Given -
1) A string is fixed at both ends and has a length of 2.34m.
2) The string vibrates at 80.6 Hz.
3) A Standing wave with five loops is generated.
Calculate
a) What is the wavelength of the waves that travel on the string?
b) What is the speed of the waves?
c) What is the fundamental fareuency of the sring?
Given:
Length of the string is L=2.34m
frequency f=80.6Hz
Number of loops are n=5
a)
The wavelength of the wave that travels on the string is given by,
Plugging all given values in above formula
We get,
or
Thus the wavelength of the wave is 0.94m.
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