1) A string is fixed at both ends and has a length of 2.34m. 2) The string vibrates at 80.6 Hz.

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Given -

1) A string is fixed at both ends and has a length of 2.34m.

2) The string vibrates at 80.6 Hz.

3) A Standing wave with five loops is generated.

Calculate

a) What is the wavelength of the waves that travel on the string?

b) What is the speed of the waves?

c) What is the fundamental fareuency of the sring?

Expert Solution
Step 1

Given:

Length of the string is L=2.34m

frequency f=80.6Hz

Number of loops are  n=5

 

Step 2

a)

The wavelength of the wave that travels on the  string is given by,

λ=2Ln

Plugging all given values in above formula

We get,

λ=2*2.345

λ=0.936m

or

λ=0.94m

Thus the wavelength of the wave is 0.94m.

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