1 A spring-loaded piston-cylinder device contains of m=1kg carbon dioxide. Initially, the spring has no force on the piston and P₁= 500kPa, ₁=150K, V₁=0.1m³. Heat is transferred to the gas, causing the piston to rise and to compress the spring. At the state 2, T₂=900K, V₂=0.3m³. The gas is an ideal gas. I ₂ (5)How to calculate the boundary work against spring W ? b-s O B. O AW₁_,- (P₁-P₁) (V2¯½₁) b-s ос. O D. W W P1, V1, T1 W = b-s = b-s b-s P2, V2, T2 (P₂+P₂)(V₂+V₂) 2 (P₁-P₁) (V₂-V₁) 2 (P₁-P₂) (V₂-V₁) 2
1 A spring-loaded piston-cylinder device contains of m=1kg carbon dioxide. Initially, the spring has no force on the piston and P₁= 500kPa, ₁=150K, V₁=0.1m³. Heat is transferred to the gas, causing the piston to rise and to compress the spring. At the state 2, T₂=900K, V₂=0.3m³. The gas is an ideal gas. I ₂ (5)How to calculate the boundary work against spring W ? b-s O B. O AW₁_,- (P₁-P₁) (V2¯½₁) b-s ос. O D. W W P1, V1, T1 W = b-s = b-s b-s P2, V2, T2 (P₂+P₂)(V₂+V₂) 2 (P₁-P₁) (V₂-V₁) 2 (P₁-P₂) (V₂-V₁) 2
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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Question
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A spring-loaded piston-cylinder device contains of m=1kg carbon dioxide. Initially, the spring has no force on the piston and , , . Heat is transferred to the gas, causing the piston to rise and to compress the spring. At the state 2, , . The gas is an ideal gas.
(5)How to calculate the boundary work against spring ?_________
A. =
B. =
C. =
D. =

Transcribed Image Text:A spring-loaded piston-cylinder device contains of m=1kg carbon dioxide. Initially, the spring has no force on the piston and P₁=500kPa,
T₁=150K, V₁₂ = 0.1m³. Heat is transferred to the gas, causing the piston to rise and to compress the spring. At the state 2, T₂=900K,
1
V₂=0.3m³. The gas is an ideal gas.
(5)How to calculate the boundary work against spring W ?
b-s
B.
O A. W₁_, (P₂-P₁) (V₂-V₁)
b-s
O C.
O D.
W
W
P1, V1, T1
b-s
W
=
=
=
b-s
b-s
P2, V2, T2
(P₂ + P₁) (V₂ + V₂)
2
(P₁-P₁) (V₂-V₁)
2
(P₁-P₂) (V₂-V₁)
2
2
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