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1-A particle moving in two dimensions has a position vector (r) as a function of time (t) with coordinates given by x(t) = t² – 4t + 20 y(t) = 3sin (2t) Where r is measured in millimetres and t is in seconds Determine the magnitude of the velocity (v) and the acceleration (a) at time t=3 s. (6-STEP METHOD)

1-A particle moving in two dimensions has a position vector (r) as a function of time (t) with coordinates given by x(t) = t² – 4t + 20 y(t) = 3sin (2t) Where r is measured in millimetres and t is in seconds Determine the magnitude of the velocity (v) and the acceleration (a) at time t=3 s. (6-STEP METHOD)

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1-A particle moving in two dimensions has a position vector (r) as a function of time (t) with coordinates given by x(t) = t² – 4t + 20 y(t) = 3sin (2t) Where r is measured in millimetres and t is in seconds Determine the magnitude of the velocity (v) and the acceleration (a) at time t=3 s. (6-STEP METHOD)
Transcribed Image Text:1-A particle moving in two dimensions has a position vector (r) as a function of time (t) with coordinates given by x(t) = t² – 4t + 20 y(t) = 3sin (2t) Where r is measured in millimetres and t is in seconds Determine the magnitude of the velocity (v) and the acceleration (a) at time t=3 s. (6-STEP METHOD)
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