1 A man pushing a mop across a floor causes it to undergo two displacements. The first has a magnitude of d₁ = 157 cm and makes an angle of ₁ = 125° with the positive x axis. The resultant displacement has a magnitude of R = 138 cm and is directed at an angle of ₂ = 33.0° to the positive x axis. Find the magnitude and direction of the second displacement. Step 1 The diagram suggests that ď₂ is larger than either of the other vectors and is in a fourth-quadrant direction. y Ꮎ . Step 2 We use the component meth subtraction. a precise answer. We already know the Step 3 The resultant displacement of the mop is R = ₂ + ď₂ 1 Then d₂ = R-d₁ Substituting, ₂ = (138✔ 138 cm at 33.0°) - (157✔ ant displacement, so the algebra of solving a vector equation will guide us to 157 cm at 125°). a

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A man pushing a mop across a floor causes it to undergo two displacements. The first has a magnitude of
positive x axis. The resultant displacement has a magnitude of R = 138 cm and is directed at an angle of
direction of the second displacement.
Step 1
The diagram suggests that d, is larger than either of the other vectors and is in a fourth-quadrant direction.
2
d₁
Then d₂ = R-d₁
1
Substituting, d
2
y
Step 2
We will use the component method for a precise answer. We already know the resultant displacement, so the algebra of solving a vector equation will guide us to do a
subtraction.
Step 3
The resultant displacement of the mop is R = ď₁ +
1
2
=
=
19₂
R
(138
138 cm at 33.0°) - 157
Step 4
The meaning of the negative sign reverses the direction of the second vector so we can rewrite the previous equation as
(138 cm at 33.0°) + (157 cm at 33
X
The response you submitted has the wrong sign.º),
which, in components, is
d₂ = [138 cos 33
+ 138 sin 125
Your response..differs from the correct answer by more than 100%.°ĵ
+ 157 cos
The response you submitted has the wrong sign.º↑ + 157 sin
Then, evaluating and collecting terms,
d₂=(
or d₂ = (
+ 90)Î + (75.2 -
î–
₁ = 157 cm and makes an angle of ₁ = 125° with the
92 = 33.0° to the positive x axis. Find the magnitude and
157 cm at 125°).
Ĵ) cm.
)Ĵ cm
°ĵ] cm.
Transcribed Image Text:A man pushing a mop across a floor causes it to undergo two displacements. The first has a magnitude of positive x axis. The resultant displacement has a magnitude of R = 138 cm and is directed at an angle of direction of the second displacement. Step 1 The diagram suggests that d, is larger than either of the other vectors and is in a fourth-quadrant direction. 2 d₁ Then d₂ = R-d₁ 1 Substituting, d 2 y Step 2 We will use the component method for a precise answer. We already know the resultant displacement, so the algebra of solving a vector equation will guide us to do a subtraction. Step 3 The resultant displacement of the mop is R = ď₁ + 1 2 = = 19₂ R (138 138 cm at 33.0°) - 157 Step 4 The meaning of the negative sign reverses the direction of the second vector so we can rewrite the previous equation as (138 cm at 33.0°) + (157 cm at 33 X The response you submitted has the wrong sign.º), which, in components, is d₂ = [138 cos 33 + 138 sin 125 Your response..differs from the correct answer by more than 100%.°ĵ + 157 cos The response you submitted has the wrong sign.º↑ + 157 sin Then, evaluating and collecting terms, d₂=( or d₂ = ( + 90)Î + (75.2 - î– ₁ = 157 cm and makes an angle of ₁ = 125° with the 92 = 33.0° to the positive x axis. Find the magnitude and 157 cm at 125°). Ĵ) cm. )Ĵ cm °ĵ] cm.
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