(1) A course repeater claims that his brother who did some Calculus at college years ago, but currently on some cough medication, believes that the first derivative of (2x² – 1)(x² + 3) f(x) = [(2x² – 1)(x² + 3) 2х + [2x² – 1 ' x² + 3 x² + 1] 4x 2х - -is f'(x) = x² +12 x² + 1 and (x² + 8)7 (x² + 8)7 (2 – 3x²)5 Using the product, qoutient and chain rules you learnt in Unit 7 of this Course, could you 30x + [x² + 8 ' 2 – 3x²] 14x that the first derivative of g(x) is g'(x) = %3D (2· 3x²)5] confirm whether his brother is right, wrong or a little tipsy.

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
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(1) A course repeater claims that his brother who did some Calculus at college years ago, but
currently on some cough medication, believes that the first derivative of
(2x2 – 1)(x² + 3)
4x
2x
2x
[(2x² – 1)(x² + 3)
f(x)
-is f'(x)
x2 + 1
[2x² – 1
x2 + 3
x2 + 1
x2 + 1
and
(x² + 8)7
14x
30x
(x² + 8)7
that the first derivative of g(x)
is g'(x) = -
+ 8
(2 — Зx?)5
3x2
(2 – 3x²)5
Using the product, qoutient and chain rules you learnt in Unit 7 of this Course, could you
2
confirm whether his brother is right, wrong or a little tipsy.
28
Transcribed Image Text:(1) A course repeater claims that his brother who did some Calculus at college years ago, but currently on some cough medication, believes that the first derivative of (2x2 – 1)(x² + 3) 4x 2x 2x [(2x² – 1)(x² + 3) f(x) -is f'(x) x2 + 1 [2x² – 1 x2 + 3 x2 + 1 x2 + 1 and (x² + 8)7 14x 30x (x² + 8)7 that the first derivative of g(x) is g'(x) = - + 8 (2 — Зx?)5 3x2 (2 – 3x²)5 Using the product, qoutient and chain rules you learnt in Unit 7 of this Course, could you 2 confirm whether his brother is right, wrong or a little tipsy. 28
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