Homework Help is Here – Start Your Trial Now!
Math
Advanced Math
(1) A course repeater claims that his brother who did some Calculus at college years ago, but currently on some cough medication, believes that the first derivative of (2x² – 1)(x² + 3), x2 +1 4х 2х 2x² – 1 x2 +3 x2 + 1] 2x 1[(2x2 – 1)(x² + 3) ] f(x) : -is f'(x) = x2 +1 and (x2 + 8)" (2 – 3x²)5 Using the product, qoutient and chain rules you learnt in Unit 7 of this Course, could you |(x² +8)7 x2 + 8 2- 3x²] [(2 – 3x²)5| 14x is g'(x) = 30x that the first derivative of g(x): confirm whether his brother is right, wrong or a little tipsy.

(1) A course repeater claims that his brother who did some Calculus at college years ago, but currently on some cough medication, believes that the first derivative of (2x² – 1)(x² + 3), x2 +1 4х 2х 2x² – 1 x2 +3 x2 + 1] 2x 1[(2x2 – 1)(x² + 3) ] f(x) : -is f'(x) = x2 +1 and (x2 + 8)" (2 – 3x²)5 Using the product, qoutient and chain rules you learnt in Unit 7 of this Course, could you |(x² +8)7 x2 + 8 2- 3x²] [(2 – 3x²)5| 14x is g'(x) = 30x that the first derivative of g(x): confirm whether his brother is right, wrong or a little tipsy.

Algebra & Trigonometry with Analytic Geometry
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter5: Inverse, Exponential, And Logarithmic Functions
Section: Chapter Questions
Problem 9T
See similar textbooks
icon
Related questions
Question

Please assist

(1) A course repeater claims that his brother who did some Calculus at college years ago, but currently on some cough medication, believes that the first derivative of (2x2 - 1)(x² + 3) 4x 2x 2x [(2x² – 1)(x2 + 3) f(x) : is f'(x) = x2 + 1 [2x2 — 1 х2 + 3 х2+ 1] x2 + 1 and (x² + 8)" (x2 + 8)7 (2 – 3x²)5 Using the product, qoutient and chain rules you learnt in Unit 7 of this Course, could you 14x 30x that the first derivative of g(x) is g'(x) = 2 + 8 2-3x²] (2 – 3x²)5] confirm whether his brother is right, wrong or a little tipsy.
Transcribed Image Text:(1) A course repeater claims that his brother who did some Calculus at college years ago, but currently on some cough medication, believes that the first derivative of (2x2 - 1)(x² + 3) 4x 2x 2x [(2x² – 1)(x2 + 3) f(x) : is f'(x) = x2 + 1 [2x2 — 1 х2 + 3 х2+ 1] x2 + 1 and (x² + 8)" (x2 + 8)7 (2 – 3x²)5 Using the product, qoutient and chain rules you learnt in Unit 7 of this Course, could you 14x 30x that the first derivative of g(x) is g'(x) = 2 + 8 2-3x²] (2 – 3x²)5] confirm whether his brother is right, wrong or a little tipsy.
Expert Solution
steps

Step by step

Solved in 5 steps

SEE SOLUTIONCheck out a sample Q&A here
Blurred answer