1) A block of mass M is constrained by rollers to motion in the x direction. A small mass m is attached at point B to the end of massless rigid arm. The other end of the arm is attached at a point A which is fixed to the cart. Together the arm and mass make up a rotor which rotates about an axis fixed at A to the cart. The angle the arm makes with a horizontal reference passing through A is given by 0 = wt. The length of the arm is "e", the distance from A to B. The position of the cart in the inertial frame is given by the coordinate xi. Find the horizontal component of the force on the mass M exerted by rod AB at t = 2s. (M = a, m = b (kg), w = axb (rad), e = b) g e B Answer:

1) A block of mass M is constrained by rollers to motion in the x direction. A small mass m is attached at point B to the end of massless rigid arm. The other end of the arm is attached at a point A which is fixed to the cart. Together the arm and mass make up a rotor which rotates about an axis fixed at A to the cart. The angle the arm makes with a horizontal reference passing through A is given by 0 = wt. The length of the arm is "e", the distance from A to B. The position of the cart in the inertial frame is given by the coordinate xi. Find the horizontal component of the force on the mass M exerted by rod AB at t = 2s. (M = a, m = b (kg), w = axb (rad), e = b) g e B Answer:

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

See similar textbooks

Related questions

Q: 2. The system of figure has degrees of freedom. ---- --- Fork Joiet Two Three Four Soring Slider…

Q: В TA A OB

A: For solution refer below image.

Q: 5- The purpose of balancing of rotating mass system is to avoid the vibrations. * False True

A: AS PER COMPANY GUIDELINES, ONLY 1 QUESTION CAN BE SOLVED AT A POST. FOR SOLUTION OF OTHER QUESTIONS,…

Q: A torque of 18 N m is applied to a rotating part. The part has a moment of inertia of 0.078 kgm2.…

A: Here we will use the the torque equation and the rotational motion equation.

Q: Find the velocity and acceleration of slider F. Also find the angular acceleration of links EPD and…

Q: In the figure shown, I=140mm, b=40mm and WAB=1100rpm (clockwise) Solve for (a) the velocity(m/s) of…

A: Given data l=140 mm b= 40mm Wab = 1100rpm thetha= 65° find the velocity of P and angular velocity…

Q: 34" C: 57 "radius 150 7. Figure P4-2

A: The instant center of rotation (also, instantaneous velocity center, instantaneous center, or…

Q: For the mechanisms shown below determine the number of links, full joints, half joints and the…

A: “Since you have posted multiple questions, we will provide the solution only to the first question…

Q: iii) Specifications: Length (in) Theta Degrees (*) Link LI 3.00 L2 6.38 25 La 4.00 L4 4.50 L3 L4 L2…

Q: 3. Find Vg and Vc AO2=30mm B AB=60mm AC=80mm BC=45mm

Q: Find Ag and Ac AO2=30mm B AB=60mm AC=80mm BC=45mm B04=50mm 0,= 2 rad/s 0204=70mm 04 Note: angle…

Q: 1. The following figure shows a four-bar linkage mechanism with its dimensions. Determine 03 and 04.…

A: The dimensions are

Q: 50000 kg

A: m1 = 60000 kgm2 = 55000 kgm3 = 50000 kgk1 =100000 kN/mk2=60000 kN/mk3= 30000 kN/m

Q: A general inverted fourbar slider-crank linkage has links length: link 2 = a = 2, link The linkage…

A: in the solution below just replace the value of theta by 60 and 90 degree

Q: Draw in a paper and specify its scale

A: Given-Information:- AC = 35 cmAB = 70 cmCD = 45 cmBD = 45 cmDE = 40 cm To-Determine:- 1.…

Q: Given b- Bm * 3m a 60 degrees R6m C 10 m Eind

A: Solution:Given,b=8mr=3m @ 60 degreesR=6mC=10m Scale(1m=1cm)

Q: For the following mechanism, Given: . • Lengths: O₂A=4 in., O;B-8 in, BC=5 in., O₂O3-4 in. and…

A: “Since you have posted a question with multiple sub parts, we will provide the solution only to the…

Q: the figure shown, I=170mm, b=70mm and wAB=1100rpm (clockwise) olve for (a) the velocity(m/s) of…

Q: 7020 First position 250mm L. 550 8660mm -350 80mm (mm) 5000. (IV) 7000. 1672.49 second positio ५००…

A: Given- A six-bar mechanism time ratio=1 Needed operations- resize the pair lim 1…

Q: Whitworth quick-return mechanism has been shown in (a). The dimensions Fig. of the links are OP…

Q: Bar AB rotates as shown with an angular velocity equal to 1O rad/s. Assume AB ha a length of 500mm…

Q: 300 mm B 600 mm A WAB Rod AB is rotating counter clockwise with an angular velocity of wAB = 50…

Q: 1 Match the following with respect to spatial mechanisms. Degrees of constraint 1. Three Type of…

A: Given Joints :- 1) Revolute Joint 2) Cylindrical Joint 3) Spherical Joint To Find :- Degree of…

Q: Please derive the two Diameter Formula for SI Units. See figure. Thank you so much Dear, your work…

A: Solution:

Q: In an open belt drive, two sheaves have diameters of 5 in. and 12 in. Determine the center distance…

A: Write the given data with suitable variables: d1=12 ind2=5 inL=72 in

Q: In the figure shown, I=155mm, b=55mm and wAB=1100rpm (clockwise) Solve for (a) the velocity(m/s) of…

Q: Find the number of cycles of all elements in the planetary mechanism in the figure. z2 = 16 z3 = 30…

A: Angular velocity is the rotational velocity of a body. It is equal to the angular distance covered…

Q: Consider an offset inverted four-bar slider crank mechanism as shown in the following figure.…

A: Given the length L2 = 6 cm,Angle is = 60oOther dimensions shown in the figure .2= 70 rad/sec² CCW2=…

Q: The length of the links are known for the mechanism shown in Figure. The angle of driver link 1…

A: The number of links is n=6 The number of binary joints is J1=7 The number of higher pairs is J2=0…

Q: intiguration. 250mm L₂= 164.35 mm O₂ = 86° 44=26mm L₁=173mm WAB-rad/s C 8₁= 90° B KAB=0.80672 rod/s²

Q: According to the below figure, if the rotational velocity of link AB is constant and equal to 2…

Concept explainers

Conservation of Energy

In physics, the rule of the conservation of energy states that energy doesn’t disappear from the atmosphere; instead, it changes its form from one type to another. Energy is one of the most important physical quantities in nature, and it cannot be created or destroyed — only transformed.

Question

M=2kg

m=2kg

w=4

e=2

omega=4t

please solve with angular motion

1) A block of mass M is constrained by rollers to motion in the x direction. A small mass m is
attached at point B to the end of massless rigid arm. The other end of the arm is attached at a
point A which is fixed to the cart. Together the arm and mass make up a rotor which rotates about
an axis fixed at A to the cart. The angle the arm makes with a horizontal reference passing through
A is given by 0 = wt. The length of the arm is "e", the distance from A to B. The position of the
cart in the inertial frame is given by the coordinate xỉ. Find the horizontal component of the force
on the mass M exerted by rod AB at t = 2s. (M = a, m = b (kg), w = axb (rad), e = b)
do
M
A
m
Answer:

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

SEE SOLUTION Check out a sample Q&A here

Step 1: Write down the given data.

VIEW

Step 2: Calculation for horizontal component of force

VIEW

Solution

VIEW

Step by step

Solved in 3 steps with 8 images

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, mechanical-engineering and related others by exploring similar questions and additional content below.

Similar questions

Q/ Crank, AB = 200 mm; Slotted arm, OC = 800 mm and link CD = 250 mm. B =30 ". find the velocity of D when the linear velocity of sliding is 1.7 m/sec ww 000 PX ww 00ɛ
Solve for all the angles. The only known angle is for m.
solve all 3. show all steps for given solutions
Solve in 15 min
Please solve analytically!!!
PROBLEM 2 the mechanism, shown on the figure, =const=5 s-¹, OA=BC=0,3 m, AB=0,6 m. Determine: a) velocity and acceleration of the point A; b) angular acceleration of the body AB; c) angular velocity and angular acceleration of the body BC; d) linear velocity and acceleration of the point B. For A B CA 120° 60⁰ @]
Given: A shaft rotates about a fixed vertical axis at a constant rate of f, as shown below. A straight bar OA, having a length of L, is pinned to point O on the shaft, with O being on the rotation axis of the shaft. At the instant when 80, bar OA is being raised at a rate of 6 from the horizontal plane, with this rate changing at a rate of . A set of ryz coordinate axes is attached to bar OA with its origin at O. A second set of coordinate axes, XYZ, are fixed to ground. At the instant when = 0, the zyz and XYZ axes are aligned with each other. Find: For the instant when -0°, determine the angular velocity and angular acceleration of har OA. vertical shaft bearing O 8 X bar Use the following parameters in your analysis: f2=5 rad/s, é = 4 rad/s, 6-3 rad/s² and L=2 m.
Can help me.
Solve
A 20-in diameter rotates at 200 RPM and a 40-in diameter pulley are used with an open belt to connect two shafts 6 ft. apart. Determine the length (inches) and speed of the belt (FPM). PLLEASE PROVIDE ILLUSTRATION
(c) In Figure Q4 (c), the 30 N block is moving up the smooth inclined surface at velocity and constant force of 2 m/s and 15 N, respectively. (i). Draw the kinetic diagram of all forces exerted on box (ii). Calculate the velocity of the block when it has moved 1 m up the surface from its present position.
1. Figure 4.11 shows a kinematic diagram of a mechanism that is driven by moving link Graphically reposition the links of the mechanism as link 2 is displaced 30° counterclockwise. Determine the resulting angular displacement of link 4 and the linear displacement of point. B 3″ AD 4.9" 90° 0 5.3" 3.3" 10.1" D 3.2"