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1) 9x- 4 2) 4k – 1 A) (5x + 1)(5x – 1) в) (4х + 3\4х — 3) с) (3х + 2X3к - 2) D) (3к - 2) A) (Sk + 4)(5k – 4) B) (2k + 1X2k – 1) c) (-2k + 1)(2k – 1) D) (2k – 1)* 3) 12n² – 27 4) 3v²au – 3u’a A) 3(-2n + 3X2n – 3) B) 3(4n + 9)² C) (2n – 3) D) 3(2n + 3)(2n – 3) A) 9a²u(-v+ u)(v– u) B) (v – u)² C) 9aªu°(v- u}² D) 3ardv+ u(v- u)

1) 9x- 4 2) 4k – 1 A) (5x + 1)(5x – 1) в) (4х + 3\4х — 3) с) (3х + 2X3к - 2) D) (3к - 2) A) (Sk + 4)(5k – 4) B) (2k + 1X2k – 1) c) (-2k + 1)(2k – 1) D) (2k – 1)* 3) 12n² – 27 4) 3v²au – 3u’a A) 3(-2n + 3X2n – 3) B) 3(4n + 9)² C) (2n – 3) D) 3(2n + 3)(2n – 3) A) 9a²u(-v+ u)(v– u) B) (v – u)² C) 9aªu°(v- u}² D) 3ardv+ u(v- u)

Algebra and Trigonometry (6th Edition)
Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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Answer this for me mate. Much appreciated.

1) 9x- 4 2) 4k – 1 A) (5x + 1)(5x – 1) в) (4х + 3\4х — 3) с) (3х + 2X3к - 2) D) (3к - 2) A) (Sk + 4)(5k – 4) B) (2k + 1X2k – 1) c) (-2k + 1)(2k – 1) D) (2k – 1)* 3) 12n² – 27 4) 3v²au – 3u’a A) 3(-2n + 3X2n – 3) B) 3(4n + 9)² с) (2n - 3) D) 3(2n + 3)(2n – 3) A) 9a²u(-v+ u)(v– u) B) (v – u)² C) 9aªu°(v– u}² D) 3adv+ u(v- u)
Transcribed Image Text:1) 9x- 4 2) 4k – 1 A) (5x + 1)(5x – 1) в) (4х + 3\4х — 3) с) (3х + 2X3к - 2) D) (3к - 2) A) (Sk + 4)(5k – 4) B) (2k + 1X2k – 1) c) (-2k + 1)(2k – 1) D) (2k – 1)* 3) 12n² – 27 4) 3v²au – 3u’a A) 3(-2n + 3X2n – 3) B) 3(4n + 9)² с) (2n - 3) D) 3(2n + 3)(2n – 3) A) 9a²u(-v+ u)(v– u) B) (v – u)² C) 9aªu°(v– u}² D) 3adv+ u(v- u)
Expert Solution
Step 1

Given 

We are given equations and we need to factorise them.

Concept used in factorization is.

a²-b² = (a-b)(a+b)

steps

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Solved in 2 steps with 1 images

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