1 7. Define Taylor's Theorem and use it to find a second order approxima- tion to (1.1)¹/4. Suppre f(x) has a +1 devivatues at a het x be some other point. Taylo's Theorem saya: 2 • point. x=a. f(x) = f(a)+ f'(a)(x-a) + f "l(a)(x-²) + - + f(a)(x-²) + R₂ 2! n! To approximate of justure first 3 termand igne the rest. ntl R₁ = f(c)(x-a)" for some (n+1)! for some cin [a, x] or [24, α] depending xsa пна. Students may not see this so igine.

College Algebra
1st Edition
ISBN:9781938168383
Author:Jay Abramson
Publisher:Jay Abramson
Chapter3: Functions
Section3.3: Rates Of Change And Behavior Of Graphs
Problem 2SE: If a functionfis increasing on (a,b) and decreasing on (b,c) , then what can be said about the local...
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can you please explain the answer by solving this question again?

4
6
7. Define Taylor's Theorem and use it to find a second order approxima-
tion to (1.1)¹/4.
Suppre f(x) has
Let x be some other point.
Taylor's Theorem
ati derivatives at a point
2
says:
f(x) = f(a)+ f(a)(x-a) + f "(a)(x-1)³ + +5 () () + un
2!
R₁ = f" (c)(x-2)^" for some cin [a,x]
(n+1)!
on [22, a] depending
To approximate of just are
first 3 termand
guine the rest.
a=1
x-α = .1
2
f(1+1) = f(i) + fin (1) + f(n) (-1)³²
2.
~ 1+1(01) - 3 (00⁰1)
4
32
~ | +.025
≈ 1.02406
8
x=a.
03
32
True vole
They don't need to show the
100271
xsa
2 x 29.
Students may.
see this so
igine.
f(x) = x +
foll=1x²³¾/4
f"(x) == 3 x
16
f(1) = 1
f'al = 4
f" (1)
ast
= -3
16
Transcribed Image Text:4 6 7. Define Taylor's Theorem and use it to find a second order approxima- tion to (1.1)¹/4. Suppre f(x) has Let x be some other point. Taylor's Theorem ati derivatives at a point 2 says: f(x) = f(a)+ f(a)(x-a) + f "(a)(x-1)³ + +5 () () + un 2! R₁ = f" (c)(x-2)^" for some cin [a,x] (n+1)! on [22, a] depending To approximate of just are first 3 termand guine the rest. a=1 x-α = .1 2 f(1+1) = f(i) + fin (1) + f(n) (-1)³² 2. ~ 1+1(01) - 3 (00⁰1) 4 32 ~ | +.025 ≈ 1.02406 8 x=a. 03 32 True vole They don't need to show the 100271 xsa 2 x 29. Students may. see this so igine. f(x) = x + foll=1x²³¾/4 f"(x) == 3 x 16 f(1) = 1 f'al = 4 f" (1) ast = -3 16
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