1-7. A 208-V, two-pole, 60-Hz, Y-connected wound-rotor induction motor is rated atI5 hp. Its equivalent circuit components areR, = 0.200 NX, = 0.410 0Pmech = 250 WXM = 15.0 NR = 0.120 NX = 0.410 0PmisePeore - 180 WFor a slip of 0.05, find(a) The line current I,(b) The stator copper losses PSCL(c) The air-gap power PAGINDUCTION MOTORS 469(d) The power converted from electrical to mechanical form Peey(e) The induced torque TindO The load torque Tioad(8) The overall machine efficiency(h) The motor speed in revolutions per minute and radians per second

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1-7. A 208-V, two-pole, 60-Hz, Y-connected wound-rotor induction motor is rated at I5 hp. Its equivalent circuit components are R = 0.120 N X = 0.4100 Paise =0 R, = 0.200 N X = 15.0N X, = 0.410 N Peec = 250 W Pen - 180 W core For a slip of 0.05, find (a) The line current I (b) The stator copper losses Psca (c) The air-gap power PAG

1-7. A 208-V, two-pole, 60-Hz, Y-connected wound-rotor induction motor is rated at I5 hp. Its equivalent circuit components are R = 0.120 N X = 0.4100 Paise =0 R, = 0.200 N X = 15.0N X, = 0.410 N Peec = 250 W Pen - 180 W core For a slip of 0.05, find (a) The line current I (b) The stator copper losses Psca (c) The air-gap power PAG

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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