1 4 5 1 To find the blue shaded area above, we would calculate: 9. f(x)dx = area a Where: a = b = f(x) :

Q: 1 dx is x2 The value of

A:

Q: B- Find dy / dx for the following functions: (3 mark) * 1- Y= sin( coshx log, 2 )

A:

Q: 1 dx (2x + 1)4

A: We will use concept of improper integral here.

Q: Determine the following: L (x - 2x2 + 1/3x) dx

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Q: Evaluate dx. /25 – x²

A: First of all, let x = 5 sin (u) and differentiate w.r.t x on both sides of the equation and find dx.

Q: To find the blue shaded area above, we would calculate: | {(2)dz = area Where: b = f(x) = Area = 2.…

A: Solve the following

Q: Differentiate the function. y = (3x- 1)* (4 - x5) 3 dy dx II

A: To differentiate the given function:

Q: Q.2 Evaluate : P;(x)dx=

A:

Q: 1. L,(3x? – 2x³)dx 2. (x? – 1)va dx

A: We will solve the problem.

Q: Q.No.3 Evaluate Sx cosec-xdx.

A: Explanation of the solution is given below....

Q: .2 dx 6. (x-1)3

A:

Q: Given the function y=sinxcoshx. Find d3y.

A: We find dy/dx using the product rule

Q: cosh x dx е e- 2х

A: Given integral is ∫coshxe-2xdx

Q: O Evalueta the definité integral

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Q: 2) Evaluate: x Inx dx

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Q: V5 sin(0) = %D 5.

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Q: Find oy for dx2

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Q: Sx tas?x dx

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Q: Q.2: Evaluate: -2 2 dx 1 I = x2 - 8.

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Q: ponit) Let f(x)dx = 4, f(x)dx = 5, f(x)dx = 5. Find f(x)dx = and (4f(x) – 5)dx = %3D

A: We have  ∫-9-3fx dx=4 ,∫-9-7fx dx=5  and ∫-5-3fx dx=5   Find ∫-7-5fx dx=? We can write the above…

Q: 1. - dx V16 – x

A: