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1 -4 1 -5 18 -2 12 12 Let A and x -19 -3 -9 8 4 13 -3 48 We want to determine if Ax b has a unique solution for every b e Rª. Choose the best answer O A. The equation has a unique solution for every b e R* because after row reducing matrix A we get a matrix without a row of zeros. OB. The equation does not have a unique solution for every b e R* because the number of rows and columns in A is the same. OC. The equation does not have a unique solution for every b e R* because after row reducing matrix A we get a matrix with a row of zeros. OD. The equation does not have a unique solution for every b e R* because after row reducing matrix A we get a matrix without a row of zeros. O E. The equation has a unique solution for every b e R* because after row reducing matrix A we get a matrix with a row of zeros. OF. The equation has a unique solution for every b e R* because the number of rows and columns in A is the same. OG. We cannot tell if the equation has a unique solution for every b e R“.

1 -4 1 -5 18 -2 12 12 Let A and x -19 -3 -9 8 4 13 -3 48 We want to determine if Ax b has a unique solution for every b e Rª. Choose the best answer O A. The equation has a unique solution for every b e R* because after row reducing matrix A we get a matrix without a row of zeros. OB. The equation does not have a unique solution for every b e R* because the number of rows and columns in A is the same. OC. The equation does not have a unique solution for every b e R* because after row reducing matrix A we get a matrix with a row of zeros. OD. The equation does not have a unique solution for every b e R* because after row reducing matrix A we get a matrix without a row of zeros. O E. The equation has a unique solution for every b e R* because after row reducing matrix A we get a matrix with a row of zeros. OF. The equation has a unique solution for every b e R* because the number of rows and columns in A is the same. OG. We cannot tell if the equation has a unique solution for every b e R“.

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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-1 -4 1 -5 4 18 -2 12 12 Let A and x = -3 -9 8 -19 I3 4 13 -3 48 We want to determine if Ax b has a unique solution for every b e Rª. Choose the best answer O A. The equation has a unique solution for every b e R* because after row reducing matrix A we get a matrix without a row of zeros. B. The equation does not have a unique solution for every b e R* because the number of rows and columns in A is the same. C. The equation does not have a unique solution for every b e R* because after row reducing matrix A we get a matrix with a row of zeros. D. The equation does not have a unique solution for every b e R* because after row reducing matrix A we get a matrix without a row of zeros. OE. The equation has a unique solution for every b e R because after row reducing matrix A we get a matrix with a row of zeros. F. The equation has a unique solution for every b e R* because the number of rows and columns in A is the same. O G. We cannot tell if the equation has a unique solution for every b e R4.
Transcribed Image Text:-1 -4 1 -5 4 18 -2 12 12 Let A and x = -3 -9 8 -19 I3 4 13 -3 48 We want to determine if Ax b has a unique solution for every b e Rª. Choose the best answer O A. The equation has a unique solution for every b e R* because after row reducing matrix A we get a matrix without a row of zeros. B. The equation does not have a unique solution for every b e R* because the number of rows and columns in A is the same. C. The equation does not have a unique solution for every b e R* because after row reducing matrix A we get a matrix with a row of zeros. D. The equation does not have a unique solution for every b e R* because after row reducing matrix A we get a matrix without a row of zeros. OE. The equation has a unique solution for every b e R because after row reducing matrix A we get a matrix with a row of zeros. F. The equation has a unique solution for every b e R* because the number of rows and columns in A is the same. O G. We cannot tell if the equation has a unique solution for every b e R4.
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