1= 300k n=0.86mok R=0.082 Latmai (4.59+m) 11) Calculate the volume, in liters, occupied by each of the following: a. 2.00 moles of H₂ at 300. K and 1.25 atm. 39.4 L 2.00 mde X 0.0821 Latm mol K x 300k -1₁,4 1.25atm b. 0.425 moles of ammonia gas (NH3) at 0.724 atm and 37°C mole . PV=nRT₁ V = nRT P=0.724a+m PV=nRT V=nRT = 39.408 39.42 P=1.25 atm V= T-300.K 1=2,00lmole R=0.082latmk mol's T=376=37+273 k= 310k 14.9 L 0.425mole (NH3)*0.0821 Latm mol kx (273+37) K- 1

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Can you help me with the number 11 question? Can you explain step by step including the formula (Ideal Gas Law)? I need to plug in the fraction to give the correct answer.
**Combined Gas Law Problems:**

1. **Problem 1:**
   - Initial conditions: \( P_1 = 12 \, \text{atm}, \, V_1 = 23 \, \text{L}, \, T_1 = 200 \, \text{K} \)
   - Final conditions: \( P_2 = 14 \, \text{atm}, \, T_2 = 300 \, \text{K} \)
   - To find: \( V_2 \)

   \[
   \frac{P_1 V_1}{T_1} = \frac{P_2 V_2}{T_2}
   \]

   Solving for \( V_2 \): 

   \[
   V_2 = \frac{P_1 V_1 T_2}{P_2 T_1} = \frac{12 \times 23 \times 300}{14 \times 200} = 29.57 \, \text{L}
   \]

2. **Problem 2:**
   - Initial conditions: \( P_1 = 2.3 \, \text{atm}, \, V_1 = 17 \, \text{L}, \, T_1 = 299 \, \text{K} \)
   - Final conditions: \( P_2 = 1.5 \, \text{atm}, \, T_2 = 350 \, \text{K} \)
   - To find: \( V_2 \)

   \[
   \frac{P_1 V_1}{T_1} = \frac{P_2 V_2}{T_2}
   \]

   Solving for \( V_2 \):

   \[
   V_2 = \frac{P_1 V_1 T_2}{P_2 T_1} = \frac{2.3 \times 17 \times 350}{1.5 \times 299} = 30.51 \, \text{L}
   \]

**Ideal Gas Law Problems:**

1. **Problem 3:**
   - Given: 1.35 moles at 320 K in 250 L
   - To find pressure: 
   
   \[
   P = \frac{nRT}{
Transcribed Image Text:**Combined Gas Law Problems:** 1. **Problem 1:** - Initial conditions: \( P_1 = 12 \, \text{atm}, \, V_1 = 23 \, \text{L}, \, T_1 = 200 \, \text{K} \) - Final conditions: \( P_2 = 14 \, \text{atm}, \, T_2 = 300 \, \text{K} \) - To find: \( V_2 \) \[ \frac{P_1 V_1}{T_1} = \frac{P_2 V_2}{T_2} \] Solving for \( V_2 \): \[ V_2 = \frac{P_1 V_1 T_2}{P_2 T_1} = \frac{12 \times 23 \times 300}{14 \times 200} = 29.57 \, \text{L} \] 2. **Problem 2:** - Initial conditions: \( P_1 = 2.3 \, \text{atm}, \, V_1 = 17 \, \text{L}, \, T_1 = 299 \, \text{K} \) - Final conditions: \( P_2 = 1.5 \, \text{atm}, \, T_2 = 350 \, \text{K} \) - To find: \( V_2 \) \[ \frac{P_1 V_1}{T_1} = \frac{P_2 V_2}{T_2} \] Solving for \( V_2 \): \[ V_2 = \frac{P_1 V_1 T_2}{P_2 T_1} = \frac{2.3 \times 17 \times 350}{1.5 \times 299} = 30.51 \, \text{L} \] **Ideal Gas Law Problems:** 1. **Problem 3:** - Given: 1.35 moles at 320 K in 250 L - To find pressure: \[ P = \frac{nRT}{
Expert Solution
Step 1

11) 

a) 2.00 moles of H2 at 300.0 K and 1.25 atm 

b) 0.425 moles of ammonia gas (NH3) at 0.724 atm and 37°C 

Using the ideal gas law: 

PV= nRT 

where , P = pressure of gas 

V = volume of gas 

n = moles of gas 

R = 0.0821 L.atm /K.mol  = constant 

T = temperature of gas 

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