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-1 2x3+1 3 Sda = In(4) + In(2) + ln(1) + ln(1).

-1 2x3+1 3 Sda = In(4) + In(2) + ln(1) + ln(1).

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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For 1-10 please answer true or false

 

Please explain why it is true

 

If false, please explain why or give a counterexample (whichever is appropriate). Recall that a counterexample is a specific example which shows that a statement is false.

x²-1 lim→-1 2a3 +1 1. Sdx = In(4) + ln(2) + ln(1) + In(1). 2. Let f be a one-to-one function with domain (-0o, 0). Then for any horizontal line L, the graph of f intersects the line L exactly once. 3. 4. Let f(x) and g(x) be any two invertible functions. Then f(x)+g(x) is an invertible function. -1 5. For any x in the domain of sin¯', we have that: x2 cos(sin-1(교)) = 4 6. Assume that f has domain (-∞, 0) and f is differentiable everywhere. If f'(x) < O for every , then f is one-to-one. For any two positive real numbers a, b such that a + 0 and b + 0 we have that In(a) · In(b) =In(a · b). 7. 8. If money is invested in an account that is continuously compounded at 4%, then it takes the same amount of time for the account to double in value no matter how much money was initially invested. 9. |sin(sin(T)) = T. For any b > 0 and b + 1, we have that limg In(1+b*) = In(b). 10.
Transcribed Image Text:x²-1 lim→-1 2a3 +1 1. Sdx = In(4) + ln(2) + ln(1) + In(1). 2. Let f be a one-to-one function with domain (-0o, 0). Then for any horizontal line L, the graph of f intersects the line L exactly once. 3. 4. Let f(x) and g(x) be any two invertible functions. Then f(x)+g(x) is an invertible function. -1 5. For any x in the domain of sin¯', we have that: x2 cos(sin-1(교)) = 4 6. Assume that f has domain (-∞, 0) and f is differentiable everywhere. If f'(x) < O for every , then f is one-to-one. For any two positive real numbers a, b such that a + 0 and b + 0 we have that In(a) · In(b) =In(a · b). 7. 8. If money is invested in an account that is continuously compounded at 4%, then it takes the same amount of time for the account to double in value no matter how much money was initially invested. 9. |sin(sin(T)) = T. For any b > 0 and b + 1, we have that limg In(1+b*) = In(b). 10.
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