1) 2N2O5 > 4NO + 302 K = 5.25 x 10-6 3.73M 3.75M 3.75M are the starting concentrations. Calculate the equilibrium concentrations to 3 significant figures.

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1) 2N2O5
4NO
302
K = 5.25 x 10-6
+
3.73M
3.75M
3.75M are the starting concentrations.
Calculate the equilibrium concentrations to 3 significant figures.
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Transcribed Image Text:1) 2N2O5 4NO 302 K = 5.25 x 10-6 + 3.73M 3.75M 3.75M are the starting concentrations. Calculate the equilibrium concentrations to 3 significant figures. No new data to save. Last checked at 10:02am F3 F4 F5 F6 F7 F8 F9 F10 F11 @ %23 & 6. 7 8. W Y U 立
Expert Solution
Step 1

In the given question, we have the following equilibrium:

2N2O54NO+3O2

When the above reaction is in equilibrium, according to the definition of equilibrium constant, we can write

K=[NO]4[O2]3[N2O5]2

Now, we have the starting materials given for each component in the equilibrium,

2N2O54NO + 3O23.73M        3.75M   3.75M

We already know that according to Le Chatelier principle, if the concentration of products is greater than that of the reactants, the equilibrium will be shifted towards left hand side direction (towards reactants).

In this case as well, the product concentrations are greater than the reactant concentration at start which means the equilibrium will be shifted towards left hand side direction.

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