-1 2 Let A = Ch 02 Sec 6 Ex 20 (c) - Inverse of a Matrix Find (A-1,3. Multiple Choice -17/120 8/120 9/120 -1/120] 8 27 -31/120 13/120 9/120 1/120 -37/125 18/125 9/125 -1/125.
-1 2 Let A = Ch 02 Sec 6 Ex 20 (c) - Inverse of a Matrix Find (A-1,3. Multiple Choice -17/120 8/120 9/120 -1/120] 8 27 -31/120 13/120 9/120 1/120 -37/125 18/125 9/125 -1/125.
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
Related questions
Question
![In this exercise, we are given a matrix \( A = \begin{bmatrix} -1 & 2 \\ 1 & 3 \end{bmatrix} \) and asked to find \((A^{-1})^3\).
### Multiple Choice Options:
1. \( \begin{bmatrix} -17/120 & 8/120 \\ 9/120 & -1/120 \end{bmatrix} \)
2. \( \begin{bmatrix} -1 & 1 \\ 8 & 27 \end{bmatrix} \)
3. \( \begin{bmatrix} -31/120 & 13/120 \\ 9/120 & 1/120 \end{bmatrix} \)
4. \( \begin{bmatrix} -37/125 & 18/125 \\ 9/125 & -1/125 \end{bmatrix} \)
Select the correct answer based on the calculation of \((A^{-1})^3\).](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fa5c3f87f-4f13-4e58-a745-fc823447281d%2F52ea4326-aafd-4bc0-9e16-28231409ac77%2Frtfg2s9_processed.png&w=3840&q=75)
Transcribed Image Text:In this exercise, we are given a matrix \( A = \begin{bmatrix} -1 & 2 \\ 1 & 3 \end{bmatrix} \) and asked to find \((A^{-1})^3\).
### Multiple Choice Options:
1. \( \begin{bmatrix} -17/120 & 8/120 \\ 9/120 & -1/120 \end{bmatrix} \)
2. \( \begin{bmatrix} -1 & 1 \\ 8 & 27 \end{bmatrix} \)
3. \( \begin{bmatrix} -31/120 & 13/120 \\ 9/120 & 1/120 \end{bmatrix} \)
4. \( \begin{bmatrix} -37/125 & 18/125 \\ 9/125 & -1/125 \end{bmatrix} \)
Select the correct answer based on the calculation of \((A^{-1})^3\).
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