= 1 2 7.3. Laboratory Tests for Rock ination Mechanical Property 1 0₁ + 0₂) + (0₁-0₂) cos 20 1/ 2 == 2 tôn) tô con - 0,) co 2 1 1 090 = (0₁ +0H) (0) 2 h 2 H-0₁) CC
= 1 2 7.3. Laboratory Tests for Rock ination Mechanical Property 1 0₁ + 0₂) + (0₁-0₂) cos 20 1/ 2 == 2 tôn) tô con - 0,) co 2 1 1 090 = (0₁ +0H) (0) 2 h 2 H-0₁) CC
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Question
Please derive the equations for sigma 0 and sigma 90 (in the blue rectangle).
Transcribed Image Text:7.3. Laboratory Tests for Rock
Mechanical Property
ination
1
1
0 = (0₁ + 0₂) +- (0₁-0₂) cos20
²
(9,-0
2
2
он
090
2
1
==
2
0 +
- 090
(0 +0%
tan 28=
+
0
1 (00-090)
cos 20
2
1 (0-090)
--
% +090-2045 = (0H - 0₁) sin 28
0
%₁-090 (OH- ) cos 28
2 cos 28
+ 090
-20₁
090
1
==
2
1
=-(00
2
=-
2
1
0 + 0 μ) + - (0 - 0) cos 26
2
1
090 == (0,₁ +0H). (OH-On) Cos 28
h
2
How to get
initial stress
values of
these 3
samples?
1
0
(0 + 090) + - (0 - 0) (1+tan²28)
90
2
% + %) — 72
11
90)
1
2
2
-90)(1+tan ² 28) ²
45°
45°
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