1 2 0 1 0 5 Given the matrix A is row equivalent to 0 0 1 -4 0 3 0 0 0 0 1 5 X = x2 + 000 000 X4 + " ☐☐☐☐☐☐ describe all solutions to Ax = 0. x6
1 2 0 1 0 5 Given the matrix A is row equivalent to 0 0 1 -4 0 3 0 0 0 0 1 5 X = x2 + 000 000 X4 + " ☐☐☐☐☐☐ describe all solutions to Ax = 0. x6
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
Related questions
Question
![Given the matrix \( A \) is row equivalent to
\[
\begin{bmatrix}
1 & -2 & 0 & 1 & 0 & 5 \\
0 & 0 & 1 & -4 & 0 & 3 \\
0 & 0 & 0 & 0 & 1 & 5 \\
\end{bmatrix}
\]
describe all solutions to \( Ax = 0 \).
The solution can be described as:
\[
x =
\begin{bmatrix}
\text{ } \\
\text{ } \\
\text{ } \\
\text{ } \\
\text{ } \\
\text{ } \\
\end{bmatrix}
= x_2
\begin{bmatrix}
\text{ } \\
\text{ } \\
\text{ } \\
\text{ } \\
\text{ } \\
\text{ } \\
\end{bmatrix}
+ x_4
\begin{bmatrix}
\text{ } \\
\text{ } \\
\text{ } \\
\text{ } \\
\text{ } \\
\text{ } \\
\end{bmatrix}
+ x_6
\begin{bmatrix}
\text{ } \\
\text{ } \\
\text{ } \\
\text{ } \\
\text{ } \\
\text{ } \\
\end{bmatrix}
\]
where each matrix represents a column vector, and \( x_2, x_4, x_6 \) are free variables corresponding to the non-pivot columns in the reduced row echelon form of the matrix \( A \). Each of these columns represents a basis vector for the solution space of the homogeneous system \( Ax = 0 \).](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F9c49f70f-02c0-4076-b0a5-564b9a6f1d8d%2Faee54cf4-59cb-401f-b02c-2041412bdec5%2Frfntxbu_processed.png&w=3840&q=75)
Transcribed Image Text:Given the matrix \( A \) is row equivalent to
\[
\begin{bmatrix}
1 & -2 & 0 & 1 & 0 & 5 \\
0 & 0 & 1 & -4 & 0 & 3 \\
0 & 0 & 0 & 0 & 1 & 5 \\
\end{bmatrix}
\]
describe all solutions to \( Ax = 0 \).
The solution can be described as:
\[
x =
\begin{bmatrix}
\text{ } \\
\text{ } \\
\text{ } \\
\text{ } \\
\text{ } \\
\text{ } \\
\end{bmatrix}
= x_2
\begin{bmatrix}
\text{ } \\
\text{ } \\
\text{ } \\
\text{ } \\
\text{ } \\
\text{ } \\
\end{bmatrix}
+ x_4
\begin{bmatrix}
\text{ } \\
\text{ } \\
\text{ } \\
\text{ } \\
\text{ } \\
\text{ } \\
\end{bmatrix}
+ x_6
\begin{bmatrix}
\text{ } \\
\text{ } \\
\text{ } \\
\text{ } \\
\text{ } \\
\text{ } \\
\end{bmatrix}
\]
where each matrix represents a column vector, and \( x_2, x_4, x_6 \) are free variables corresponding to the non-pivot columns in the reduced row echelon form of the matrix \( A \). Each of these columns represents a basis vector for the solution space of the homogeneous system \( Ax = 0 \).
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