[1 -1 Let = 1 -3 .An eigenvalue of A is A = -2. Find a basis for the corresponding 14 -13 1 eigenspace.

Elementary Linear Algebra (MindTap Course List)
8th Edition
ISBN:9781305658004
Author:Ron Larson
Publisher:Ron Larson
Chapter7: Eigenvalues And Eigenvectors
Section7.1: Eigenvalues And Eigenvectors
Problem 76E: Define T:P2P2 by T(a0+a1x+a2x2)=(2a0+a1a2)+(a1+2a2)xa2x2. Find the eigenvalues and the eigenvectors...
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[1 0
Let = 1 -3
14 -13
0 . An eigenvalue of A is A = -2. Find a basis for the corresponding
1
eigenspace.
Transcribed Image Text:[1 0 Let = 1 -3 14 -13 0 . An eigenvalue of A is A = -2. Find a basis for the corresponding 1 eigenspace.
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