1 1 Helium is compressed through a compressor steadily. At the inlet the pressure is P₁ = 100kPa and the temperature is T₁=300K. At the exit the pressure is P₂ = 600kPa and the temperature is T=390K. The power input is W=5000kW and the heat loss rate is Q = 1000k//s during 1 2 out this process. Neglect the kinetic and potential energy changes. Assume helium is ideal gas with a constant specific heat c=5.1926 kJ/kg . K and its P specific heat ratio k == 1.667, which means that enthalpy can be calculated using h=c_T. Calculate the enthalpy per unit mass at the P C exit h kJ/kg
1 1 Helium is compressed through a compressor steadily. At the inlet the pressure is P₁ = 100kPa and the temperature is T₁=300K. At the exit the pressure is P₂ = 600kPa and the temperature is T=390K. The power input is W=5000kW and the heat loss rate is Q = 1000k//s during 1 2 out this process. Neglect the kinetic and potential energy changes. Assume helium is ideal gas with a constant specific heat c=5.1926 kJ/kg . K and its P specific heat ratio k == 1.667, which means that enthalpy can be calculated using h=c_T. Calculate the enthalpy per unit mass at the P C exit h kJ/kg
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
Related questions
Question
Helium is compressed through a compressor steadily. At the inlet the pressure is and the temperature is . At the exit the pressure is and the temperature is . The power input is and the heat loss rate is during this process. Neglect the kinetic and potential energy changes. Assume helium is ideal gas with a constant specific heat and its specific heat ratio , which means that enthalpy can be calculated using . Calculate the enthalpy per unit mass at the exit _________
![**Helium Compression Analysis**
Helium is compressed through a compressor steadily. At the inlet, the pressure is \( P_1 = 100 \, \text{kPa} \) and the temperature is \( T_1 = 300 \, \text{K} \). At the exit, the pressure is \( P_2 = 600 \, \text{kPa} \) and the temperature is \( T_2 = 390 \, \text{K} \).
The system has a power input of \( \dot{W} = 5000 \, \text{kW} \) and the heat loss rate is \( \dot{Q}_{\text{out}} = 1000 \, \text{kJ/s} \) during this process. Neglect the kinetic and potential energy changes.
Assumptions:
- The helium behaves as an ideal gas.
- Constant specific heat \( c_p = 5.1926 \, \text{kJ/kg} \cdot \text{K} \).
- Specific heat ratio \( k = \frac{c_p}{c_v} = 1.667 \).
Using the relation \( h = c_p \cdot T \), you are to calculate the enthalpy per unit mass at the exit.
**Calculation:**
Determine the enthalpy \( h_2 \) in \(\text{kJ/kg}\).
\[
h_2 = \underline{\hspace{3cm}} \, \text{kJ/kg}
\]
**Use the provided data and equations to find \( h_2 \).**](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F72d490d0-ea92-4353-8b1a-fc4847a9a9b3%2F588cee2c-4af5-43c9-b618-6e4cc7ff283f%2Fgjg7avm_processed.png&w=3840&q=75)
Transcribed Image Text:**Helium Compression Analysis**
Helium is compressed through a compressor steadily. At the inlet, the pressure is \( P_1 = 100 \, \text{kPa} \) and the temperature is \( T_1 = 300 \, \text{K} \). At the exit, the pressure is \( P_2 = 600 \, \text{kPa} \) and the temperature is \( T_2 = 390 \, \text{K} \).
The system has a power input of \( \dot{W} = 5000 \, \text{kW} \) and the heat loss rate is \( \dot{Q}_{\text{out}} = 1000 \, \text{kJ/s} \) during this process. Neglect the kinetic and potential energy changes.
Assumptions:
- The helium behaves as an ideal gas.
- Constant specific heat \( c_p = 5.1926 \, \text{kJ/kg} \cdot \text{K} \).
- Specific heat ratio \( k = \frac{c_p}{c_v} = 1.667 \).
Using the relation \( h = c_p \cdot T \), you are to calculate the enthalpy per unit mass at the exit.
**Calculation:**
Determine the enthalpy \( h_2 \) in \(\text{kJ/kg}\).
\[
h_2 = \underline{\hspace{3cm}} \, \text{kJ/kg}
\]
**Use the provided data and equations to find \( h_2 \).**
Expert Solution

This question has been solved!
Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.
Step by step
Solved in 2 steps with 2 images

Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, mechanical-engineering and related others by exploring similar questions and additional content below.Recommended textbooks for you

Elements Of Electromagnetics
Mechanical Engineering
ISBN:
9780190698614
Author:
Sadiku, Matthew N. O.
Publisher:
Oxford University Press

Mechanics of Materials (10th Edition)
Mechanical Engineering
ISBN:
9780134319650
Author:
Russell C. Hibbeler
Publisher:
PEARSON

Thermodynamics: An Engineering Approach
Mechanical Engineering
ISBN:
9781259822674
Author:
Yunus A. Cengel Dr., Michael A. Boles
Publisher:
McGraw-Hill Education

Elements Of Electromagnetics
Mechanical Engineering
ISBN:
9780190698614
Author:
Sadiku, Matthew N. O.
Publisher:
Oxford University Press

Mechanics of Materials (10th Edition)
Mechanical Engineering
ISBN:
9780134319650
Author:
Russell C. Hibbeler
Publisher:
PEARSON

Thermodynamics: An Engineering Approach
Mechanical Engineering
ISBN:
9781259822674
Author:
Yunus A. Cengel Dr., Michael A. Boles
Publisher:
McGraw-Hill Education

Control Systems Engineering
Mechanical Engineering
ISBN:
9781118170519
Author:
Norman S. Nise
Publisher:
WILEY

Mechanics of Materials (MindTap Course List)
Mechanical Engineering
ISBN:
9781337093347
Author:
Barry J. Goodno, James M. Gere
Publisher:
Cengage Learning

Engineering Mechanics: Statics
Mechanical Engineering
ISBN:
9781118807330
Author:
James L. Meriam, L. G. Kraige, J. N. Bolton
Publisher:
WILEY