Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Question
please solve 183,191
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number.
191. y = √x from x =
= 2 to x = 6
192. y = x³ from x = 0 to x = 1
193. y = 7x from x = -1 to x = 1
194. [T] y = from x = 1 to x = 3
X
195. y = √4x² from x =
= 0 to x = 2
2
196. y = √4x² from x = -1 to x = 1
-
197. y = 5x from x = 1 to x = 5
198. [T] y tan x from x = -4to x = 4
For the following exercises, find the surface area of the
solid generated when the following curves revolve
around the y-axis. Write your result as an exact
number.
199. y = x² from x = 0 to x = 2
2
1.0
у 0.5
0.0
-2
Page <
1
0
X
PortalGuard Sir X
2
1
> of 5
2
Homework 4 - X
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208. A light bulb is a sphere with radius 1/2 in. with the
bottom sliced off to fit exactly onto a cylinder of radius
1/4 in. and length 1/3 in., as seen here. The sphere is
cut off at the bottom to fit exactly onto the cylinder, so
the radius of the cut is 1/4 in. Find the surface area (not
including the top or bottom of the cylinder).
71°F
209. [T] A lampshade is constructed by rotating y = 1/x
around the x-axis from y = 1 to y = 2, as seen here.
Determine how much material you would need to construct
this lampshade-that is, the surface area-accurate to four
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Homework - Vol2 - Section 2.4 - Arc Length of a Curve and Surface Area.pdf
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number.
191. y = √x from x =
= 2 to x = 6
192. y = x³ from x = 0 to x = 1
193. y = 7x from x = -1 to x = 1
194. [T] y = from x = 1 to x = 3
X
195. y = √4x² from x =
= 0 to x = 2
2
196. y = √4x² from x = -1 to x = 1
-
197. y = 5x from x = 1 to x = 5
198. [T] y tan x from x = -4to x = 4
For the following exercises, find the surface area of the
solid generated when the following curves revolve
around the y-axis. Write your result as an exact
number.
199. y = x² from x = 0 to x = 2
2
1.0
у 0.5
0.0
-2
Page <
1
0
X
PortalGuard Sir X
2
1
> of 5
2
Homework 4 - X
Download
208. A light bulb is a sphere with radius 1/2 in. with the
bottom sliced off to fit exactly onto a cylinder of radius
1/4 in. and length 1/3 in., as seen here. The sphere is
cut off at the bottom to fit exactly onto the cylinder, so
the radius of the cut is 1/4 in. Find the surface area (not
including the top or bottom of the cylinder).
71°F
209. [T] A lampshade is constructed by rotating y = 1/x
around the x-axis from y = 1 to y = 2, as seen here.
Determine how much material you would need to construct
this lampshade-that is, the surface area-accurate to four
✪
+
i Info
ZOOM +
T
X Close
7:53 PM
9/17/2022
X
:
My
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Homework - Vol2 - Section 2.4 - Arc Length of a Curve and Surface Area.pdf
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-1
-2
1
2
X
3
4
2
-2
-1
2
170. Find the surface area of the volume generated when
the curve y = x² revolves around the y-axis from (1, 1)
to (3,9).
This OpenStax book is available for free at http://cnx.org/content/col11965/1.2
182.
181. y = 5-3x from y=0 to y = 4
= Hey.
183.
For the following exercises, find the lengths of
the functions of y over the given interval. Write
your result as an exact number.
185.
X =
186.
Page
3/2
= 5y³ from y = 0 to y = 1
184. [T] x = y² from y = 0 to y = 1
X =
= √√y from y = 0 to y = 1
X =
PortalGuard Sir X
1 > of 5
+
+e) from y = -1 to y = 1
Ď
3/2
x =
= ²/(x²-
(y² + 1) from y = 1 to y = 3
188. [T] x = cos² y from y =
187. [T] x = tan y from y = 0 to y =
플 to
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||
EN
Homework 4 - X
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Homework - Vol2 - Section 2.4 - Arc Length of a Curve and Surface Area.pdf
Type here to search
-1
-2
1
2
X
3
4
2
-2
-1
2
170. Find the surface area of the volume generated when
the curve y = x² revolves around the y-axis from (1, 1)
to (3,9).
This OpenStax book is available for free at http://cnx.org/content/col11965/1.2
182.
181. y = 5-3x from y=0 to y = 4
= Hey.
183.
For the following exercises, find the lengths of
the functions of y over the given interval. Write
your result as an exact number.
185.
X =
186.
Page
3/2
= 5y³ from y = 0 to y = 1
184. [T] x = y² from y = 0 to y = 1
X =
= √√y from y = 0 to y = 1
X =
PortalGuard Sir X
1 > of 5
+
+e) from y = -1 to y = 1
Ď
3/2
x =
= ²/(x²-
(y² + 1) from y = 1 to y = 3
188. [T] x = cos² y from y =
187. [T] x = tan y from y = 0 to y =
플 to
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Homework 4 - X
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Expert Solution
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