[1 0 Let A =|0 1 1/3 0 1/13 1/3 Numerically verify that each initial state vector xo has the given steady-state vector x. 0.26 0.59 X0 =| 0.08 »| 0.41 0.66 0.42 0.47 X1 =| 0.48 | = 0.53 0.1 0.48 Axo = 0.3 Ax1 = 0.22 A*x A*x1 %3D A®xo = A$x1 =

[1 0 Let A =|0 1 1/3 0 1/13 1/3 Numerically verify that each initial state vector xo has the given steady-state vector x. 0.26 0.59 X0 =| 0.08 »| 0.41 0.66 0.42 0.47 X1 =| 0.48 | = 0.53 0.1 0.48 Axo = 0.3 Ax1 = 0.22 Ax Ax1 %3D A®xo = A$x1 =

Algebra and Trigonometry (6th Edition)

6th Edition

ISBN:9780134463216

Author:Robert F. Blitzer

Publisher:Robert F. Blitzer

ChapterP: Prerequisites: Fundamental Concepts Of Algebra

Section: Chapter Questions

Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...

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0.7 [8]. 0.3 Is q = a steady-state vector for A= 0.7 0.3 0.3 0.7 ? Justify your answer. Select the correct choice below and, if necessary, fill in the answer box to complete your choice. O A. The vector q is a steady state vector because the sum of its entries is 1 and Aq = q. B. The vector q is not a steady state vector because the sum of its entries is (Type an integer or a decimal.) OC. The vector q is not a steady state vector because Aq= (Type an integer or decimal for each matrix element.) so Aq #q.
0 1/3 1 1/3 0 0 1/3 Numerically verify that each initial state vector xo has the given steady-state vector x. [0.575 0.425 0 0.68 1 Let A = 0 Xo = 0.27 0.31 0.49 X1 x₁ = 0.13 0.38 Axo = 0.421 A4x0 = A³xo = ⇒ 0.32 0 Ax₁ = 841 A4x₁ = A³x₁ =
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