[-1 0 87 -4 3 8 -2 07 has a single real elgenvalue λ = 3 with algebraic multiplicity three. (a) Find a basis for the associated eigenspace. The matrix A= Basis = (b) is the matrix A defective? DA. A is defective because the geometric multiplicity of the eigenvalue is less than the algebraic multiplicity OB. A is not defective because the elgenvectors are linearly independent Oc. A is defective because it has only one eigenvalue OD. A is not defective because the eigenvalue has algebraic multiplicity three
[-1 0 87 -4 3 8 -2 07 has a single real elgenvalue λ = 3 with algebraic multiplicity three. (a) Find a basis for the associated eigenspace. The matrix A= Basis = (b) is the matrix A defective? DA. A is defective because the geometric multiplicity of the eigenvalue is less than the algebraic multiplicity OB. A is not defective because the elgenvectors are linearly independent Oc. A is defective because it has only one eigenvalue OD. A is not defective because the eigenvalue has algebraic multiplicity three
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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![T-1 0 81
The matrix A = -4 3 8
-2 07
has a single real elgenvalue λ = 3 with algebraic multiplicity three.
(a) Find a basis for the associated elgenspace.
Basis =
(b) Is the matrix A defective?
DA. A is defective because the geometric multiplicity of the eigenvalue is less than the algebraic multiplicity
OB. A is not defective because the elgenvectors are linearly independent
Oc. A is defective because it has only one eigenvalue
OD. A is not defective because the eigenvalue has algebraic multiplicity three](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ffb2133c9-e1e5-4d56-9c72-044227328930%2F3b2ce927-470e-4054-a966-f7fc80fb449e%2F9wb6lsf_processed.jpeg&w=3840&q=75)
Transcribed Image Text:T-1 0 81
The matrix A = -4 3 8
-2 07
has a single real elgenvalue λ = 3 with algebraic multiplicity three.
(a) Find a basis for the associated elgenspace.
Basis =
(b) Is the matrix A defective?
DA. A is defective because the geometric multiplicity of the eigenvalue is less than the algebraic multiplicity
OB. A is not defective because the elgenvectors are linearly independent
Oc. A is defective because it has only one eigenvalue
OD. A is not defective because the eigenvalue has algebraic multiplicity three
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