1 0 3 0 -1 2 0 6 Let A= 0 -3 -6 0 -2 0 0 -92 0 -2 6 0 -1-2 2 -9 -1 0 0 0 -1 [10 3 0-1 0-1 0 0120 3 0 reduced row echelon form of A is 0 0 0 1 -3 0) 00000 1 00000 0 0 Row Space basis: Column Space basis: Null Space basis: Rank: Nullity: UD U Find a basis for the row space of A, a basis for the column space of A, a basis for the null space of A, the rank of A, and the nullity of A. (Note that the

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Question
Linear algebra -p2
0
[10 3 0 -1 0
-2
0 -9
-2 6 0
-2 2 -9 -1
2 0 6 0
Let A= 0 -3 -6
0 0 0
0-1-2
[1 0 3 0 -1 0
0120 3 0
reduced row echelon form of Ais 0 0 0 1 -3 0)
0 1
00
Row Space basis:
Column Space basis:
Null Space basis:
Rank:
Nullity:
2. Find a basis for the row space of A, a basis for the column space of A, a basis for the null space of A, the rank of A, and the nullity of A. (Note that the
U
0000
10000 0
Transcribed Image Text:0 [10 3 0 -1 0 -2 0 -9 -2 6 0 -2 2 -9 -1 2 0 6 0 Let A= 0 -3 -6 0 0 0 0-1-2 [1 0 3 0 -1 0 0120 3 0 reduced row echelon form of Ais 0 0 0 1 -3 0) 0 1 00 Row Space basis: Column Space basis: Null Space basis: Rank: Nullity: 2. Find a basis for the row space of A, a basis for the column space of A, a basis for the null space of A, the rank of A, and the nullity of A. (Note that the U 0000 10000 0
Expert Solution
Step 1

The given matrix is A=1030-102060-200-3-60-92000-2600-1-22-9-1

The row echelon form of A is B=1030-100120300001-30000001000000.

Now we have to find 

(a) Row space basis

(b) Column space basis

(c) Null space basis

(d) Rank

(e) Nullity.

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