0610908 - Introduction to Electrical Phase 1 8 of 20 Which DMM measurement would you expect based upon the red and black leads in this image? 12 V O-4 V O OV O 4 V O 12 V ww 8 V 4V OV

Introductory Circuit Analysis (13th Edition)
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Chapter1: Introduction
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**Electrical Phase 1: Voltage Measurement**

**Module: Introduction to Electrical Phase 1**

**Page: 8 of 20**

**Question:**

Which DMM (Digital Multimeter) measurement would you expect based upon the red and black leads in this image?

**Diagram Explanation:**

The diagram illustrates an electrical circuit with a series of voltages across different segments. The circuit includes:

- A 12 V source.
- A circuit path broken down into sections marked with voltages: 12 V, 8 V, 4 V, and 0 V.
- A ground symbol is connected at the end of the circuit path.

**Measurement Setup:**

- The black lead of the DMM is placed at the 4 V point on the circuit.
- The red lead of the DMM is placed at the 0 V point (ground).

**Possible DMM Readings:**

- \(-4 \text{ V}\)
- \(0 \text{ V}\)
- \(4 \text{ V}\)
- \(12 \text{ V}\)

**Expected Answer:**

The expected measurement is \(-4 \text{ V}\) because the red lead is connected to a lower potential (0 V) relative to the black lead (4 V), resulting in a negative voltage reading.
Transcribed Image Text:**Electrical Phase 1: Voltage Measurement** **Module: Introduction to Electrical Phase 1** **Page: 8 of 20** **Question:** Which DMM (Digital Multimeter) measurement would you expect based upon the red and black leads in this image? **Diagram Explanation:** The diagram illustrates an electrical circuit with a series of voltages across different segments. The circuit includes: - A 12 V source. - A circuit path broken down into sections marked with voltages: 12 V, 8 V, 4 V, and 0 V. - A ground symbol is connected at the end of the circuit path. **Measurement Setup:** - The black lead of the DMM is placed at the 4 V point on the circuit. - The red lead of the DMM is placed at the 0 V point (ground). **Possible DMM Readings:** - \(-4 \text{ V}\) - \(0 \text{ V}\) - \(4 \text{ V}\) - \(12 \text{ V}\) **Expected Answer:** The expected measurement is \(-4 \text{ V}\) because the red lead is connected to a lower potential (0 V) relative to the black lead (4 V), resulting in a negative voltage reading.
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