06 dollars. You will use a simple random sample of 125 uto insurance policies. ind the probability that a single randomly selected policy as a mean value between 991.5 and 1007.7 dollars. (991.5 X 1007.7) = < ind the probability that a random sample of size n = 125 as a mean value between 991.5 and 1007.7 dollars. (991.5 M 1007.7) = <

MATLAB: An Introduction with Applications
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ISBN:9781119256830
Author:Amos Gilat
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Chapter1: Starting With Matlab
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CNNBC recently reported that the mean annual cost of auto
insurance is 983 dollars. Assume the standard deviation is
106 dollars. You will use a simple random sample of 125
auto insurance policies.
Find the probability that a single randomly selected policy
has a mean value between 991.5 and 1007.7 dollars.
P(991.5 < X < 1007.7) =
Find the probability that a random sample of size n = 125
has a mean value between 991.5 and 1007.7 dollars.
P(991.5 M 1007.7) =
<
Enter your answers as numbers accurate to 4 decimal
places.
Transcribed Image Text:CNNBC recently reported that the mean annual cost of auto insurance is 983 dollars. Assume the standard deviation is 106 dollars. You will use a simple random sample of 125 auto insurance policies. Find the probability that a single randomly selected policy has a mean value between 991.5 and 1007.7 dollars. P(991.5 < X < 1007.7) = Find the probability that a random sample of size n = 125 has a mean value between 991.5 and 1007.7 dollars. P(991.5 M 1007.7) = < Enter your answers as numbers accurate to 4 decimal places.
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