06 (a) A stationary particle 1 decays into particles 2 and 3, which move off with equal but oppositely directed momenta. Show that the kinetic energy K2 of particle 2 is given by K, -[(E, - E) – E, 2E, where E1, E2, and Ez are the rest energies of the particles. (b) A stationary positive pion + (rest energy 139.6 MeV) can de- cay to an antimuon ut (rest energy 105.7 MeV) and a neutrino v (rest energy approximately 0). What is the resulting kinetic energy of the antimuon?

College Physics
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Chapter1: Units, Trigonometry. And Vectors
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06 (a) A stationary particle 1 decays into particles 2 and 3, which
move off with equal but oppositely directed momenta. Show that
the kinetic energy K2 of particle 2 is given by
K,
-[(E, - E) – E,
2E,
where E1, E2, and Ez are the rest energies of the particles.
(b) A stationary positive pion + (rest energy 139.6 MeV) can de-
cay to an antimuon ut (rest energy 105.7 MeV) and a neutrino v
(rest energy approximately 0). What is the resulting kinetic energy
of the antimuon?
Transcribed Image Text:06 (a) A stationary particle 1 decays into particles 2 and 3, which move off with equal but oppositely directed momenta. Show that the kinetic energy K2 of particle 2 is given by K, -[(E, - E) – E, 2E, where E1, E2, and Ez are the rest energies of the particles. (b) A stationary positive pion + (rest energy 139.6 MeV) can de- cay to an antimuon ut (rest energy 105.7 MeV) and a neutrino v (rest energy approximately 0). What is the resulting kinetic energy of the antimuon?
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