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06 (a) A stationary particle 1 decays into particles 2 and 3, which move off with equal but oppositely directed momenta. Show that the kinetic energy K2 of particle 2 is given by K, -[(E, - E) – E, 2E, where E1, E2, and Ez are the rest energies of the particles. (b) A stationary positive pion + (rest energy 139.6 MeV) can de- cay to an antimuon ut (rest energy 105.7 MeV) and a neutrino v (rest energy approximately 0). What is the resulting kinetic energy of the antimuon?

06 (a) A stationary particle 1 decays into particles 2 and 3, which move off with equal but oppositely directed momenta. Show that the kinetic energy K2 of particle 2 is given by K, -[(E, - E) – E, 2E, where E1, E2, and Ez are the rest energies of the particles. (b) A stationary positive pion + (rest energy 139.6 MeV) can de- cay to an antimuon ut (rest energy 105.7 MeV) and a neutrino v (rest energy approximately 0). What is the resulting kinetic energy of the antimuon?

Principles of Physics: A Calculus-Based Text
Principles of Physics: A Calculus-Based Text
5th Edition
ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
Publisher:Raymond A. Serway, John W. Jewett
Chapter9: Relativity
Section9.7: Relativistic Energy
Problem 9.6QQ: The following pairs of energiesparticle 1: E, 2E; particle 2: E, 3E; particle 3: 2E, 4Erepresent the...
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06 (a) A stationary particle 1 decays into particles 2 and 3, which move off with equal but oppositely directed momenta. Show that the kinetic energy K2 of particle 2 is given by K, -[(E, - E) – E, 2E, where E1, E2, and Ez are the rest energies of the particles. (b) A stationary positive pion + (rest energy 139.6 MeV) can de- cay to an antimuon ut (rest energy 105.7 MeV) and a neutrino v (rest energy approximately 0). What is the resulting kinetic energy of the antimuon?
Transcribed Image Text:06 (a) A stationary particle 1 decays into particles 2 and 3, which move off with equal but oppositely directed momenta. Show that the kinetic energy K2 of particle 2 is given by K, -[(E, - E) – E, 2E, where E1, E2, and Ez are the rest energies of the particles. (b) A stationary positive pion + (rest energy 139.6 MeV) can de- cay to an antimuon ut (rest energy 105.7 MeV) and a neutrino v (rest energy approximately 0). What is the resulting kinetic energy of the antimuon?
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