031811582 031811582 031811 82 031811582 03181158 V* = +5 V 031811582 031811582 031811582 0O 811582 031811582 03181158 031811582 031811582 031811582 031811582 031811582 03181158 031811582 031811582 031811582 01+11582 031811582 03181158 031811582 031811582 0318115 2 031V1582 031811582 03181158 031811582 031811582 0318115 031811582 031811582 03181158 031811582 0318115 031811582 031811582 031811582 03181158 RR = 250 kS2 < 031811582 01811582 031811582 03181158 031811582 0318112 031811582 811582 031811582 03181158 031811582 031811582 031811582 Rc= 1.5 kM OS18T1582 03181158 031811582 031811 031811582 01811582 031811582 03181158 031811582 031811582 031811582 031811582 031811582 03181158 031811582 031811582 031811582 01811582 031811582 03181158 V==-5 V %3D 031811582 031811582 031 811 82 031811582 03181158

Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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Question
β=200. Q operating point(Ic,Vec) ?
 
 
 
 
 
 
 
031811582 031811582 031811v+ 231 2 031811582 03181158
= +5 V
031811582 031811582 031811582 01811582 031811582 03181158
031811582 031811582 031811582 031811582 031811582 03181158
031811582 031811582 031811582 0+11582 031811582 03181158
031811582 031811582 0318115 2 0311582 031811582 03181158
EC
031811582 031811582 0318115 031811582 031811582 03181158
031811582 03181152 031811582 01811582 031811582 03181158
o
RR = 250 ks2 < 031811582 01811582 031811582 03181158
031811582 0318112 031811582 811582 031811582 03181158
031811582 031811582 031811582 RC= 1.5 k2
031811582 0318112 031811582 031811582 031811582 03181158
1811582 03181158
031811582 031811582 031811582 01811582 031811582 03181158
031811582 031811582 031811582 0 811582 031811582 03181158
V==-5 V
II
031811582 031811582 031811382 031811582 031811582 03181158
Transcribed Image Text:031811582 031811582 031811v+ 231 2 031811582 03181158 = +5 V 031811582 031811582 031811582 01811582 031811582 03181158 031811582 031811582 031811582 031811582 031811582 03181158 031811582 031811582 031811582 0+11582 031811582 03181158 031811582 031811582 0318115 2 0311582 031811582 03181158 EC 031811582 031811582 0318115 031811582 031811582 03181158 031811582 03181152 031811582 01811582 031811582 03181158 o RR = 250 ks2 < 031811582 01811582 031811582 03181158 031811582 0318112 031811582 811582 031811582 03181158 031811582 031811582 031811582 RC= 1.5 k2 031811582 0318112 031811582 031811582 031811582 03181158 1811582 03181158 031811582 031811582 031811582 01811582 031811582 03181158 031811582 031811582 031811582 0 811582 031811582 03181158 V==-5 V II 031811582 031811582 031811382 031811582 031811582 03181158
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