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02 of 2) i) Convert i(t) = 4 sin(6t – 60°) A to phasor form: ii) If L = 50mH with w=1000 rad/s, what is Z₁ = = iii) If R = 1092 with w=1000 rad/s, what is ZR iv) If C = 0.1mF with w=1000 rad/w, what is Zc = v) Change V = 8 260° V into time domain form if w = 250 rad/s:_ vi) If ZR = 10 and Z₁ = j15 ₪ and they are parallel to each other, Find their Zeq in polar form? Show work, box answer: vii) Given the following circuit, with V = 40 <30° V, Z₁ = 10 N, Z₂ = j6 N, Z3 = −j2 N. Find the current I in phasor form, i.e. I(w), and box answer. Show all steps. Z₁ 2₂ Z3

02 of 2) i) Convert i(t) = 4 sin(6t – 60°) A to phasor form: ii) If L = 50mH with w=1000 rad/s, what is Z₁ = = iii) If R = 1092 with w=1000 rad/s, what is ZR iv) If C = 0.1mF with w=1000 rad/w, what is Zc = v) Change V = 8 260° V into time domain form if w = 250 rad/s:_ vi) If ZR = 10 and Z₁ = j15 ₪ and they are parallel to each other, Find their Zeq in polar form? Show work, box answer: vii) Given the following circuit, with V = 40 <30° V, Z₁ = 10 N, Z₂ = j6 N, Z3 = −j2 N. Find the current I in phasor form, i.e. I(w), and box answer. Show all steps. Z₁ 2₂ Z3

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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## Question 2 of 2 ### i) Convert \( i(t) = 4 \sin(6t - 60^\circ) \) A to phasor form: \[ \text{Phasor form:} \ \_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_ \] ### ii) If \( L = 50 \text{ mH} \) with \(\omega = 1000 \text{ rad/s}\), what is \( Z_L \): \[ Z_L = \_\_\_\_\_\_\_\_\_\_\_\_\_\_\_ \] ### iii) If \( R = 10 \Omega \) with \( \omega = 1000 \text{ rad/s} \), what is \( Z_R \): \[ Z_R = \_\_\_\_\_\_\_\_\_\_\_\_\_\_\_ \] ### iv) If \( C = 0.1 \text{ mF} \) with \( \omega = 1000 \text{ rad/w} \), what is \( Z_C \): \[ Z_C = \_\_\_\_\_\_\_\_\_\_\_\_\_\_\_ \] ### v) Change \( V = 8 \angle 60^\circ \ \text{V} \) into time domain form if \( \omega = 250 \text{ rad/s} \): \[ \text{Time domain form:} \ \_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_ \] ### vi) If \( Z_R = 10 \ \Omega \) and \( Z_L = j15 \ \Omega \) and they are parallel to each other, find their \( Z_{eq} \) in polar form: \[ \text{Show work, Box answer:} \] ### vii) Given the following circuit, with \( V = 40 \angle 30^\circ \ \text{V} \), \( Z_1 = 10 \ \Omega \), \( Z_2 = j6 \ \Omega \), \( Z_3 = -j2 \ \Omega \). Find the current \( I \) in phasor form, i.e. \( I(\omega) \), and box answer. Show all steps. --- #### Detailed Graph/Drawing Explanation: The
Transcribed Image Text:## Question 2 of 2 ### i) Convert \( i(t) = 4 \sin(6t - 60^\circ) \) A to phasor form: \[ \text{Phasor form:} \ \_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_ \] ### ii) If \( L = 50 \text{ mH} \) with \(\omega = 1000 \text{ rad/s}\), what is \( Z_L \): \[ Z_L = \_\_\_\_\_\_\_\_\_\_\_\_\_\_\_ \] ### iii) If \( R = 10 \Omega \) with \( \omega = 1000 \text{ rad/s} \), what is \( Z_R \): \[ Z_R = \_\_\_\_\_\_\_\_\_\_\_\_\_\_\_ \] ### iv) If \( C = 0.1 \text{ mF} \) with \( \omega = 1000 \text{ rad/w} \), what is \( Z_C \): \[ Z_C = \_\_\_\_\_\_\_\_\_\_\_\_\_\_\_ \] ### v) Change \( V = 8 \angle 60^\circ \ \text{V} \) into time domain form if \( \omega = 250 \text{ rad/s} \): \[ \text{Time domain form:} \ \_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_ \] ### vi) If \( Z_R = 10 \ \Omega \) and \( Z_L = j15 \ \Omega \) and they are parallel to each other, find their \( Z_{eq} \) in polar form: \[ \text{Show work, Box answer:} \] ### vii) Given the following circuit, with \( V = 40 \angle 30^\circ \ \text{V} \), \( Z_1 = 10 \ \Omega \), \( Z_2 = j6 \ \Omega \), \( Z_3 = -j2 \ \Omega \). Find the current \( I \) in phasor form, i.e. \( I(\omega) \), and box answer. Show all steps. --- #### Detailed Graph/Drawing Explanation: The
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