02 for the function : a x Find x² sin ( y³ + x e³z - cos ( z? ) = 3 y - 6 z + 8 .A 2 x sin ( 3y ) + 3e3z -6 - 3x e3z - 2 z sin ( 2z) dz .B 2 z sin ( z? ) cos ( y ) + e3z +6 - 3 x e3z az a x %3D 2х .C dz 32 2 x sin (y3) + e dx 6 - 3x e3z – 2 z sin ( z?) .D dz Зу?x 2сos (y3) -з дх —6 — 3хез 3z - 2 z sin ( z²) II

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Question
Find
dZ for the function :
a x
3z
x2 sin ( y³ ) + x e³²
cos ( z? ) = 3 y - 6 z + 8
.A
dz
2 x sin (3y ) + 3e3z
-6 - 3x e3z – 2 z sin (2z )
dx
.B
a z
6 - 3 x e3z
- 2 z sin ( z² )
a x
2х
cos ( y )
3z
e
.C
2 x sin (y3) + e3z
6 — Зхез2
dz
%3D
dx
2 z sin (z2)
.D
Зу?x?сos (у3) -з
-6 - 3x e3z - 2 z sin (z?)
dz
Əx
|
Transcribed Image Text:Find dZ for the function : a x 3z x2 sin ( y³ ) + x e³² cos ( z? ) = 3 y - 6 z + 8 .A dz 2 x sin (3y ) + 3e3z -6 - 3x e3z – 2 z sin (2z ) dx .B a z 6 - 3 x e3z - 2 z sin ( z² ) a x 2х cos ( y ) 3z e .C 2 x sin (y3) + e3z 6 — Зхез2 dz %3D dx 2 z sin (z2) .D Зу?x?сos (у3) -з -6 - 3x e3z - 2 z sin (z?) dz Əx |
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