02) and gaseo is the theoretical yield of water formed from the reaction of 9.95 g of methane and 11.5 g of oxygen gas? bus methane (CH4) reacts with gaseous oxygen gas (02) to produce gaseous carbon dioxide d your answer to 3 significant figures.

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**Title: Calculating Theoretical Yield in Chemical Reactions**

**Introduction**

Understanding the theoretical yield of a chemical reaction is essential in fields such as chemistry and chemical engineering. Here, we present a simple example to illustrate how to calculate the theoretical yield of water produced in a chemical reaction.

---

**Problem Statement**

Gaseous methane (CH₄) reacts with gaseous oxygen gas (O₂) to produce gaseous carbon dioxide (CO₂) and gaseous water (H₂O).

**Given:**
- 9.95 grams of methane (CH₄)
- 11.5 grams of oxygen gas (O₂)

**Question:**
What is the theoretical yield of water formed from the reaction of the given amounts of methane and oxygen gas?

**Note:** Round your answer to 3 significant figures.

---

**Reaction Equation**

The balanced chemical equation for the reaction is:

\[ \text{CH}_4 + 2\text{O}_2 \rightarrow \text{CO}_2 + 2\text{H}_2\text{O} \]

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**Steps to Calculate Theoretical Yield:**

**1. Calculate the Molar Mass:**
- Molar mass of CH₄: 12 (C) + 4 × 1 (H) = 16 g/mol
- Molar mass of O₂: 2 × 16 (O) = 32 g/mol
- Molar mass of H₂O: 2 × 1 (H) + 16 (O) = 18 g/mol

**2. Convert Grams to Moles:**
- Moles of CH₄: 
  \[ \frac{9.95 \text{ g}}{16 \text{ g/mol}} = 0.622 \text{ mol} \]
  
- Moles of O₂: 
  \[ \frac{11.5 \text{ g}}{32 \text{ g/mol}} = 0.359 \text{ mol} \]

**3. Determine the Limiting Reagent:**
From the balanced equation, 1 mole of CH₄ reacts with 2 moles of O₂.

- Moles of O₂ needed for 0.622 mol of CH₄:
  \[ 0.622 \text{ mol CH}_4 \times 2 \text{ mol O}_2/\text{mol CH
Transcribed Image Text:**Title: Calculating Theoretical Yield in Chemical Reactions** **Introduction** Understanding the theoretical yield of a chemical reaction is essential in fields such as chemistry and chemical engineering. Here, we present a simple example to illustrate how to calculate the theoretical yield of water produced in a chemical reaction. --- **Problem Statement** Gaseous methane (CH₄) reacts with gaseous oxygen gas (O₂) to produce gaseous carbon dioxide (CO₂) and gaseous water (H₂O). **Given:** - 9.95 grams of methane (CH₄) - 11.5 grams of oxygen gas (O₂) **Question:** What is the theoretical yield of water formed from the reaction of the given amounts of methane and oxygen gas? **Note:** Round your answer to 3 significant figures. --- **Reaction Equation** The balanced chemical equation for the reaction is: \[ \text{CH}_4 + 2\text{O}_2 \rightarrow \text{CO}_2 + 2\text{H}_2\text{O} \] --- **Steps to Calculate Theoretical Yield:** **1. Calculate the Molar Mass:** - Molar mass of CH₄: 12 (C) + 4 × 1 (H) = 16 g/mol - Molar mass of O₂: 2 × 16 (O) = 32 g/mol - Molar mass of H₂O: 2 × 1 (H) + 16 (O) = 18 g/mol **2. Convert Grams to Moles:** - Moles of CH₄: \[ \frac{9.95 \text{ g}}{16 \text{ g/mol}} = 0.622 \text{ mol} \] - Moles of O₂: \[ \frac{11.5 \text{ g}}{32 \text{ g/mol}} = 0.359 \text{ mol} \] **3. Determine the Limiting Reagent:** From the balanced equation, 1 mole of CH₄ reacts with 2 moles of O₂. - Moles of O₂ needed for 0.622 mol of CH₄: \[ 0.622 \text{ mol CH}_4 \times 2 \text{ mol O}_2/\text{mol CH
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