01 int convertBinaryToOctal (long binaryNo) { 02 0; 03 04 05 06 07 08 09 10 11 12 13 14 15 16 17 18 } int octalNo ++i; binaryNo } = = while (binaryNo != 0) { decimalNo = decimalNo + (binaryNo%0) pow (2, i); binaryNo 10; 0, decimal No decimalNo i = 1 * 10; = } i = 1; while (decimalNo != 0) { octalNooctalNo + (decimalNo%8) * I; decimalNo / 8; 0, i return octalNo;

Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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Draw the control flow graph for variable ‘decimalNo’ based on the image given

01 int convertBinaryToOctal (long binaryNo) {
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int octalNo = 0, decimal No
while (binaryNo != 0) {
decimalNo = decimalNo + (binaryNo%0) * pow (2,1);
++i;
binaryNo
binaryNo 10;
=
}
=
}
i = 1;
while (decimalNo != 0) {
octalNo = octalNo + (decimalNo%8)
decimal No
decimalNo 8;
i = i * 10;
=
0, i = 0;
return octalNo;
* I;
Transcribed Image Text:01 int convertBinaryToOctal (long binaryNo) { 02 03 04 05 06 07 08 09 10 11 12 13 14 15 16 17 18 } int octalNo = 0, decimal No while (binaryNo != 0) { decimalNo = decimalNo + (binaryNo%0) * pow (2,1); ++i; binaryNo binaryNo 10; = } = } i = 1; while (decimalNo != 0) { octalNo = octalNo + (decimalNo%8) decimal No decimalNo 8; i = i * 10; = 0, i = 0; return octalNo; * I;
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