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0001 = Load AC from memory 0010 = Store AC to memory 0101 = Add to AC from memory 0011 = Load AC (the accumulator register) from an I/O device 0111 = Store AC to an I/O device With these instructions, a particular I/O device is identified by replacing the 12-bit address portion with a 12-bit device number. Remember that a number ending with a small ‘h’ means the number is a hexadecimal number. What is the hexadecimal string that expresses the following instructions? Load AC from memory location 62h.  Add the contents of memory location 451h to AC.  Store AC to memory location 8h.  Store AC to I/O device number 8h.

0001 = Load AC from memory 0010 = Store AC to memory 0101 = Add to AC from memory 0011 = Load AC (the accumulator register) from an I/O device 0111 = Store AC to an I/O device With these instructions, a particular I/O device is identified by replacing the 12-bit address portion with a 12-bit device number. Remember that a number ending with a small ‘h’ means the number is a hexadecimal number. What is the hexadecimal string that expresses the following instructions? Load AC from memory location 62h.  Add the contents of memory location 451h to AC.  Store AC to memory location 8h.  Store AC to I/O device number 8h.

Computer Networking: A Top-Down Approach (7th Edition)
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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0001 = Load AC from memory

0010 = Store AC to memory

0101 = Add to AC from memory

0011 = Load AC (the accumulator register) from an I/O device

0111 = Store AC to an I/O device

With these instructions, a particular I/O device is identified by replacing the 12-bit address portion with a 12-bit device number. Remember that a number ending with a small ‘h’ means the number is a hexadecimal number.

What is the hexadecimal string that expresses the following instructions?

  1. Load AC from memory location 62h. 
  2. Add the contents of memory location 451h to AC. 
  3. Store AC to memory location 8h. 
  4. Store AC to I/O device number 8h.
пуроше IImachiIne in Memory 300 1 9 4 0 301 5 9 4 1 302 29 41 CPU registers 30 0 PC Memory 300 1 9 4 0 AC 301 5 9 4 1 1940 IR 302 29 4 1 CPU registers 30 1 PC 0 00 3 AC 194 0 IR 940 0 0 0 3 941 0 0 0 2 940 0 0 0 3 941 0 00 2 Step 1 Step 2 Memory 300 1 9 4 0 301 5 9 41 302 29 4 1 CPU registers 30 1 PC 0 00 3 AC 301 5 9 4 1 5 94 1 IR 302 29 4 1 CPU registers 30 2 PC 0 0 0 5 AC 5 9 4 1IR Memory 300 19 4 0 940 0 0 0 3 941 0 0 0 2 940 0 00 3 941 0 0 0 2 Step 3 Step 4 Memory 300 1 9 4 0 301 5 9 4 1 302 2 9 4 I CPU registers 30 2 PC 0 0 0 5 AC 301 5 9 4 1 294 1 IR 302 2 9 4 1 Memory CPU registers 30 3 PC 0 00 5 AC 294 1 IR 300 19 4 0 940 0 0 0 3 941 0 0 0 2 940 0 0 03 941 0 0 0 5 Step 5 Step 6
Transcribed Image Text:пуроше IImachiIne in Memory 300 1 9 4 0 301 5 9 4 1 302 29 41 CPU registers 30 0 PC Memory 300 1 9 4 0 AC 301 5 9 4 1 1940 IR 302 29 4 1 CPU registers 30 1 PC 0 00 3 AC 194 0 IR 940 0 0 0 3 941 0 0 0 2 940 0 0 0 3 941 0 00 2 Step 1 Step 2 Memory 300 1 9 4 0 301 5 9 41 302 29 4 1 CPU registers 30 1 PC 0 00 3 AC 301 5 9 4 1 5 94 1 IR 302 29 4 1 CPU registers 30 2 PC 0 0 0 5 AC 5 9 4 1IR Memory 300 19 4 0 940 0 0 0 3 941 0 0 0 2 940 0 00 3 941 0 0 0 2 Step 3 Step 4 Memory 300 1 9 4 0 301 5 9 4 1 302 2 9 4 I CPU registers 30 2 PC 0 0 0 5 AC 301 5 9 4 1 294 1 IR 302 2 9 4 1 Memory CPU registers 30 3 PC 0 00 5 AC 294 1 IR 300 19 4 0 940 0 0 0 3 941 0 0 0 2 940 0 0 03 941 0 0 0 5 Step 5 Step 6
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