00000000 : 0: lea 0x4(%esp),%ecx 4: and $0xfffffff0,%esp 7: pushl -0x4(%ecx) a: push %ebp b: mov %esp,%ebp d: push %ebx e: push %ecx f: sub $0x10,%esp 12: mov %ecx,%ebx 14: movl $0x0,-0xc(%ebp) 1b: movl $0x1,-0x10(%ebp) 22: jmp 48 24: mov -0x10(%ebp),%eax 27: lea 0x0(,%eax,4),%edx 2e: mov 0x4(%ebx),%eax 31: add %edx,%eax 33: mov (%eax),%eax 35: sub $0xc,%esp 38: push %eax 39: call 3a 3e: add $0x10,%esp 41: add %eax,-0xc(%ebp) 44: addl $0x1,-0x10(%ebp) 48: mov -0x10(%ebp),%eax 4b: cmp (%ebx),%eax 4d: jl 24 4f: mov -0xc(%ebp),%eax 52: lea -0x8(%ebp),%esp 55: pop %ecx 56: pop %ebx 57: pop %ebp 58: lea -0x4(%ecx),%esp 5b: ret Command line arguments are passed to int main(int argc, char** argv) as arguments argc and argv. You should assume that argc is at ebp+8 and argv is at ebp+12. This code returns the following value from main (in register eax): Question options: 1) product of the command line arguments 2) sum of the command line arguments 3) number of characters in the command line arguments 4) how many command line arguments were provided

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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Question

00000000 <main>:
0: lea 0x4(%esp),%ecx
4: and $0xfffffff0,%esp
7: pushl -0x4(%ecx)
a: push %ebp
b: mov %esp,%ebp
d: push %ebx
e: push %ecx
f: sub $0x10,%esp
12: mov %ecx,%ebx
14: movl $0x0,-0xc(%ebp)
1b: movl $0x1,-0x10(%ebp)
22: jmp 48 <main+0x48>
24: mov -0x10(%ebp),%eax
27: lea 0x0(,%eax,4),%edx
2e: mov 0x4(%ebx),%eax
31: add %edx,%eax
33: mov (%eax),%eax
35: sub $0xc,%esp
38: push %eax
39: call 3a <main+0x3a>
3e: add $0x10,%esp
41: add %eax,-0xc(%ebp)
44: addl $0x1,-0x10(%ebp)
48: mov -0x10(%ebp),%eax
4b: cmp (%ebx),%eax
4d: jl 24 <main+0x24>
4f: mov -0xc(%ebp),%eax
52: lea -0x8(%ebp),%esp
55: pop %ecx
56: pop %ebx
57: pop %ebp
58: lea -0x4(%ecx),%esp
5b: ret

Command line arguments are passed to int main(int argc, char** argv) as arguments argc and argv. You should assume that argc is at ebp+8 and argv is at ebp+12.

This code returns the following value from main (in register eax):

Question options:

1)	product of the command line arguments

2)	sum of the command line arguments

3)	number of characters in the command line arguments

4)	how many command line arguments were provided

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