00 Show that 8 Σ anx" n=3 n=4 Σ nbnx" n=4 How can the two series be combined into a single sum? _n-1 n+1 A. Adjust the sums so that the starting indices are the same. B. Adjust the sums so that the coefficients are the same. C. Adjust the sums so that the coefficients have the same index. D. Adjust the sums so that the summands are the same. Adjust the sums so they can be combined. 8 Σ apanti 8 Σ (Γ n+1 = n=3 n= + 00 3 4b4x³+ Σ = n= 00 00 n-1 Σnbnx = 4b4x³+ Σ [8an-1 + (n+1)bn+1]x". n=4 n=4 Combine the sums to complete the proof. 00 3 4b4x + Σ n=

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
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The task is to show that the equation:

\[ 8 \sum_{n=3}^{\infty} a_n x^{n+1} + \sum_{n=4}^{\infty} nb_n x^{n-1} = 4b_4 x^3 + \sum_{n=4}^{\infty} \left[ 8a_{n-1} + (n+1)b_n \right] x^n. \]

consists of several parts to solve:

1. **Index Adjustment Section:**
   - There are boxes for setting \( n = 4 \) for both starting indices \( n = 3 \) and \( n = 4 \). This allows both series to start at the same index.

2. **Series Combination Question:**
   - A multiple-choice question asks: "How can the two series be combined into a single sum?" with options: 
     - A. Adjust sums to have the same starting indices.
     - B. Adjust sums so coefficients are the same.
     - C. Adjust sums so coefficients have the same index.
     - D. Adjust sums so summands are the same.

3. **Sum Adjustment Section:**
   - The equation boxes suggest rewriting as:
     \[
     8 \sum_{n=3}^{\infty} a_n x^{n+1} = 8 \sum_{n=\square}^{\infty} (\square),
     \]
     \[
     \sum_{n=4}^{\infty} nb_n x^{n-1} = 4b_4 x^3 + \sum_{n=\square}^{\infty} (\square),
     \]
   This section prompts filling in indices and terms such that the series can be properly combined.

4. **Final Proof:**
   - The bottom section asks to combine the sums to finish the proof:
     \[
     4b_4 x^3 + \sum_{n=\square}^{\infty} (\square).
     \]

This activity involves finding and adjusting indices and terms to create a unified sum, ultimately proving the original equation through algebraic manipulation.
Transcribed Image Text:The task is to show that the equation: \[ 8 \sum_{n=3}^{\infty} a_n x^{n+1} + \sum_{n=4}^{\infty} nb_n x^{n-1} = 4b_4 x^3 + \sum_{n=4}^{\infty} \left[ 8a_{n-1} + (n+1)b_n \right] x^n. \] consists of several parts to solve: 1. **Index Adjustment Section:** - There are boxes for setting \( n = 4 \) for both starting indices \( n = 3 \) and \( n = 4 \). This allows both series to start at the same index. 2. **Series Combination Question:** - A multiple-choice question asks: "How can the two series be combined into a single sum?" with options: - A. Adjust sums to have the same starting indices. - B. Adjust sums so coefficients are the same. - C. Adjust sums so coefficients have the same index. - D. Adjust sums so summands are the same. 3. **Sum Adjustment Section:** - The equation boxes suggest rewriting as: \[ 8 \sum_{n=3}^{\infty} a_n x^{n+1} = 8 \sum_{n=\square}^{\infty} (\square), \] \[ \sum_{n=4}^{\infty} nb_n x^{n-1} = 4b_4 x^3 + \sum_{n=\square}^{\infty} (\square), \] This section prompts filling in indices and terms such that the series can be properly combined. 4. **Final Proof:** - The bottom section asks to combine the sums to finish the proof: \[ 4b_4 x^3 + \sum_{n=\square}^{\infty} (\square). \] This activity involves finding and adjusting indices and terms to create a unified sum, ultimately proving the original equation through algebraic manipulation.
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