0=0 E=2€₁ 26₁ 여 [E = olk A As described in class, the electric field contribution from just the positive, red colored plate because of Use + to denote directions to the everywhere to its left is right and to denote directions to the left. Assume the symbol Q refers to a positive charge.
0=0 E=2€₁ 26₁ 여 [E = olk A As described in class, the electric field contribution from just the positive, red colored plate because of Use + to denote directions to the everywhere to its left is right and to denote directions to the left. Assume the symbol Q refers to a positive charge.
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Question
![### Image Transcription and Explanation
The image illustrates two parallel plates, each with an electric charge. The left plate has a negative charge density denoted as \(-\sigma\), and the right plate has a positive charge density denoted as \(\sigma\).
#### Diagram Explanation:
- **Left Plate (Negative Plate):**
- Charge density: \(-\sigma\)
- The electric field (\(E\)) contribution from this plate is directed to the right and given by the formula:
\[
E = \frac{\sigma}{2\varepsilon_0}
\]
- **Right Plate (Positive Plate):**
- Charge density: \(\sigma = \frac{Q}{A}\)
- The entire electric field (\(E\)) from this plate is also pointing to the right, calculated as:
\[
E = \frac{\sigma}{2\varepsilon_0}
\]
- **Net Electric Field (\(\Sigma E\)):**
- The net electric field between the plates is:
\[
\Sigma E = \frac{\sigma}{\varepsilon_0}
\]
#### Accompanying Text:
"As described in class, the electric field contribution from just the positive, red colored plate everywhere to its left is ______ because of ______. Use + to denote directions to the right and - to denote directions to the left. Assume the symbol Q refers to a positive charge."
#### Multiple Choice Options:
1. \(\frac{\sigma}{2\varepsilon_0}\), superposition
2. 0, superposition
3. \(\frac{\sigma}{2\varepsilon_0}\), superposition
4. \(\frac{\sigma}{2\varepsilon_0}\), Gauss's law
5. \(\frac{\sigma}{2\varepsilon_0}\), Gauss's law
This setup relates to understanding the principles of electric fields generated by charged plates, and how these principles apply using superposition or Gauss's law.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F9f5a9711-32c0-4fd9-a0b2-a9c57acc4509%2F5c8c3236-e85c-4b9e-a55c-539e7a835392%2Fcsqsq1o_processed.jpeg&w=3840&q=75)
Transcribed Image Text:### Image Transcription and Explanation
The image illustrates two parallel plates, each with an electric charge. The left plate has a negative charge density denoted as \(-\sigma\), and the right plate has a positive charge density denoted as \(\sigma\).
#### Diagram Explanation:
- **Left Plate (Negative Plate):**
- Charge density: \(-\sigma\)
- The electric field (\(E\)) contribution from this plate is directed to the right and given by the formula:
\[
E = \frac{\sigma}{2\varepsilon_0}
\]
- **Right Plate (Positive Plate):**
- Charge density: \(\sigma = \frac{Q}{A}\)
- The entire electric field (\(E\)) from this plate is also pointing to the right, calculated as:
\[
E = \frac{\sigma}{2\varepsilon_0}
\]
- **Net Electric Field (\(\Sigma E\)):**
- The net electric field between the plates is:
\[
\Sigma E = \frac{\sigma}{\varepsilon_0}
\]
#### Accompanying Text:
"As described in class, the electric field contribution from just the positive, red colored plate everywhere to its left is ______ because of ______. Use + to denote directions to the right and - to denote directions to the left. Assume the symbol Q refers to a positive charge."
#### Multiple Choice Options:
1. \(\frac{\sigma}{2\varepsilon_0}\), superposition
2. 0, superposition
3. \(\frac{\sigma}{2\varepsilon_0}\), superposition
4. \(\frac{\sigma}{2\varepsilon_0}\), Gauss's law
5. \(\frac{\sigma}{2\varepsilon_0}\), Gauss's law
This setup relates to understanding the principles of electric fields generated by charged plates, and how these principles apply using superposition or Gauss's law.
Expert Solution
Step 1
Gauss law: According to this law. surface integral of the electric field along a closed surface is equal to times the charge stored in the volume covered by that closed surface. Mathematically it can be written as,
where is the electric field, is the charge, is the permittivity of free space, and is the area vector perpendicular to the surface.
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