0.8x1 - 0.4x2 = 41 -0.4x1 + 0.8x2 - 0.4x3 = 25 -0.4x2 +0.8x3= 105 The value of the variables on the above system of equations at the end of the first iteration using Gauss-Seidel method with Relaxation coefficient (A=1.2) and initial

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Chapter2: Second-order Linear Odes
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Numerical 1
Given:
0.8x1 - 0.4x2 = 41
-0.4x1 + 0.8x2 - 0.4x3 = 25
-0.4x2 +0.8x3= 105
The value of the variables on the above
system of equations at the end of the first
iteration using Gauss-Seidel method with
Relaxation coefficient (A=1.2) and initial
guesses x1=0, x2=0, and x3=0 will be:
a. X1=167.8711, x2=244.3887,
X3=253.6222
O b. X1=71.75, x2=79.625, x3=223.5625
O c. X1=61.5, X2=74.4, x3=202.14
d. X1=10.25, x2=11.375, X3=31.9375
e. X1=51.25, x2=56.875, x3=159.6875
O f. X1=61.5, X2=68.25, x3=191.625
Transcribed Image Text:Given: 0.8x1 - 0.4x2 = 41 -0.4x1 + 0.8x2 - 0.4x3 = 25 -0.4x2 +0.8x3= 105 The value of the variables on the above system of equations at the end of the first iteration using Gauss-Seidel method with Relaxation coefficient (A=1.2) and initial guesses x1=0, x2=0, and x3=0 will be: a. X1=167.8711, x2=244.3887, X3=253.6222 O b. X1=71.75, x2=79.625, x3=223.5625 O c. X1=61.5, X2=74.4, x3=202.14 d. X1=10.25, x2=11.375, X3=31.9375 e. X1=51.25, x2=56.875, x3=159.6875 O f. X1=61.5, X2=68.25, x3=191.625
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