0.700 moles of an unknown solid is placed into water to make 150.0 mL of solution. The solution's temperature decreases by 8.51 °C. Calculate AH, in kJ/mol, for the dissolution of the unknown solid. (The specific heat of the solution is 4.184 J/g. °C and the density of the solution is 1.02 g/mL).
0.700 moles of an unknown solid is placed into water to make 150.0 mL of solution. The solution's temperature decreases by 8.51 °C. Calculate AH, in kJ/mol, for the dissolution of the unknown solid. (The specific heat of the solution is 4.184 J/g. °C and the density of the solution is 1.02 g/mL).
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![0.700 moles of an unknown solid is placed into water to make
150.0 mL of solution. The solution's temperature decreases by
8.51 °C. Calculate AH, in kJ/mol, for the dissolution of the
unknown solid. (The specific heat of the solution is 4.184 J/g.
°C and the density of the solution is 1.02 g/mL).](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F1ec17e88-d660-4bdb-bdfb-b19af12326ab%2F063a15f2-38fd-417b-af5c-b9788fa6a8a7%2F9lxgdjg_processed.jpeg&w=3840&q=75)
Transcribed Image Text:0.700 moles of an unknown solid is placed into water to make
150.0 mL of solution. The solution's temperature decreases by
8.51 °C. Calculate AH, in kJ/mol, for the dissolution of the
unknown solid. (The specific heat of the solution is 4.184 J/g.
°C and the density of the solution is 1.02 g/mL).
Expert Solution
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Step 1: Calculate the heat (q) absorbed or released during the temperature change.
Answer :--
Using the formula for heat (q) is :-
q = m⋅C⋅ΔT
m (mass of the solution) = ρ⋅V (density × volume)
C (specific heat capacity of the solution) = 4.184 J/g·°C
ΔT (temperature change) = 8.51°C
Now, substitute the values are :-
q = 153.0g × 4.184J/g⋅°C × 8.51°C
= 5447.69J
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