0.666 66 - 033333 D.3335 1.40 O.666 b6 -0.33333 +0. 3'33 33 45 find u=? Ansaer: e=2158-so545

Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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### Transcription and Explanation

This mathematical solution involves solving an equation for a variable, denoted as \( u \), by using an exponential expression. Below is a transcription and explanation.

#### Given Equation:
\[ 
1.10 = 45 \left[ 1 (e^t)^{-0.33333} \right] - 15 \left[ 1 - 1 (e^t)^{-0.33333} \right]^{0.66666}
\]

#### Steps:
1. **Substitution:**
   - Let \( e^t = u \).

2. **Rewriting the Equation:**
   - Substitute \( u \) into the equation to get:
   \[
   1.10 = 45 \left[ u^{-0.33333} \right] - 15 \left[ 1 - u^{-0.33333} \right]^{0.66666}
   \]

3. **Goal:**
   - Find the value of \( u \).

4. **Solution Box:**
   - The solution gives:
     \[
     u = 2158.54545
     \]
   - Calculating \( t \) using the natural logarithm function:
     \[
     t = \ln(2158.54545)
     \]
   - Resulting in:
     \[
     t = 7.627
     \]

This transcription provides the step-by-step transformation and illustration of the calculus involved in finding \( u \) and further calculations to evaluate \( t \).
Transcribed Image Text:### Transcription and Explanation This mathematical solution involves solving an equation for a variable, denoted as \( u \), by using an exponential expression. Below is a transcription and explanation. #### Given Equation: \[ 1.10 = 45 \left[ 1 (e^t)^{-0.33333} \right] - 15 \left[ 1 - 1 (e^t)^{-0.33333} \right]^{0.66666} \] #### Steps: 1. **Substitution:** - Let \( e^t = u \). 2. **Rewriting the Equation:** - Substitute \( u \) into the equation to get: \[ 1.10 = 45 \left[ u^{-0.33333} \right] - 15 \left[ 1 - u^{-0.33333} \right]^{0.66666} \] 3. **Goal:** - Find the value of \( u \). 4. **Solution Box:** - The solution gives: \[ u = 2158.54545 \] - Calculating \( t \) using the natural logarithm function: \[ t = \ln(2158.54545) \] - Resulting in: \[ t = 7.627 \] This transcription provides the step-by-step transformation and illustration of the calculus involved in finding \( u \) and further calculations to evaluate \( t \).
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